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vichka [17]
3 years ago
7

Which of these correctly lists the stages of development of the inner planets?

Chemistry
2 answers:
Inessa [10]3 years ago
7 0
The answer to the question stated above is letter <span>B. heavier elements ® planetesimals ® protoplanets ® inner planets

The formation of the inner planets undergo different</span><span> stages of development.  These are:
</span><span>heavier elements > planetesimals >protoplanets > inner planets

</span>
ZanzabumX [31]3 years ago
5 0
The correct answer for the question that is being presented above is this one:  "C. planetesimals ® heavier elements ® inner planets ® protoplanets" The list of the stages of development of the inner planets is this <span>C. planetesimals ® heavier elements ® inner planets ® protoplanets</span>
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Explain how you determine the freezing point of a solution that does not have a well-defined transition in the cooling curve.
Sophie [7]

This question is asking for a method for the determination of the freezing point in a solution that does not have a noticeable transition in the cooling curve, which is basically based on a linear fit method.

The first step, would be to understand that when the transition is well-defined as the one on the attached file, we can just identify the temperature by just reading the value on the graph, at the time the slope has a pronounced change. For instance, on the attached, the transition occurs after about 43 seconds and the freezing point will be about 4 °C.

However, when we cannot identify a pronounced change in the slope, it will be necessary to use a linear fit method (such as minimum squares) to figure out the equation for each segmented line having a significantly different slope and then equal them so that we can numerically solve for the intercept.

As an example, imagine two of the segmented lines have the following equations after applying the linear fit method:

y=-3.5 x + 25\\\\y=-0.52 x + 2

First of all, we equal them to find the x-value, in this case the time at which the freezing point takes place:

-3.5 x + 25=-0.52 x + 2\\\\-3.5 x+0.52 x =2-25\\\\x=\frac{-23}{-2.98}=7.72

Next, we plug it in in any of the trendlines to obtain the freezing point as the y-value:

y=-3.5 (7.72) + 25\\\\y = 1.84

This means the freezing point takes place after 7.72 second of cooling and is about 1.84 °C. Now you can replicate it for any not well-defined cooling curve.

Learn more:

  • brainly.com/question/22818252
  • brainly.com/question/9680530

7 0
3 years ago
Write down moleculer formula:
Temka [501]
1. Ca(HCO3)2
2.Ca(HCOO)2
3. Ca(OH)2
4.NaOH
5.KCI
6.MgSO4
7.PbO
8.HCl
9.HNO3
10.H2SO4
11.NH3
12.(NH4)3PO4
13.NaOH
:)
5 0
3 years ago
Read 2 more answers
Both __________ and __________ can be classified as pure substances because they have distinct properties and composition.
musickatia [10]

Answer:

Both <u>elements </u>and <u>compounds</u> can be classifies as pure substances because they have distinct properties and composition.

Explanation:

Elements and compounds are considered as pure substances because both are always formed form are have same kind of atoms.

For example,

Carbon dioxide is compound. It always consist of one carbon atom and two oxygen atoms.

Water is compound it always have same kind of atoms two hydrogen and one oxygen that's why compounds are considered as pure substances.

Same is the case with elements. For example,

Hydrogen is element and it always consist of H atoms.

Iron is another element and it always have iron atoms.

So elements and compounds are always consist of same substances that's why they are considered as pure.

4 0
3 years ago
Someone help please this is due today!!?
maria [59]

Answer:

I think beaker three will take longer to boil since there is more water present,compared to the other beakers

3 0
2 years ago
The chemical equation of magnesium and nitric acid
marshall27 [118]
Mg + 2H(NO)3 ⇒ Mg(NO3)2 + H2
5 0
3 years ago
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