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vichka [17]
3 years ago
7

Which of these correctly lists the stages of development of the inner planets?

Chemistry
2 answers:
Inessa [10]3 years ago
7 0
The answer to the question stated above is letter <span>B. heavier elements ® planetesimals ® protoplanets ® inner planets

The formation of the inner planets undergo different</span><span> stages of development.  These are:
</span><span>heavier elements > planetesimals >protoplanets > inner planets

</span>
ZanzabumX [31]3 years ago
5 0
The correct answer for the question that is being presented above is this one:  "C. planetesimals ® heavier elements ® inner planets ® protoplanets" The list of the stages of development of the inner planets is this <span>C. planetesimals ® heavier elements ® inner planets ® protoplanets</span>
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Which of the following best describes the solar radiation absorbed by and radiated from earth?
FinnZ [79.3K]

Answer:

the answer that you are looking for is d

Explanation:

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Which units represent destiny? Select all that apply.
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The basic units for density is \frac{mass}{volume} and any get of units that has those units in the proper place can be considered a density unit.  The ones that has those specifically are A, B, E and F
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Given bh3, o3, co2, and nh3, which of these compound is an exception to the octet rules?.
Ghella [55]

Answer:

a. BH₃

Explanation:

According to the octet rules, atoms reach stability when are surrounded by eight electrons in their valence shell when they combine to form a chemical compound.

From the options, the only compound in which the central atom does not meet the octet rules is BH₃. The central atom is boron (B), which has 3 electrons in its valence shell. When B is combined with hydrogen (H), 3 electrons from the 3 atoms of H are added. The total amount of electrons is 6, fewer than 8 electrons needed to meet the rule.

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5 0
2 years ago
Select the correct answer. Which of these elements is a transition metal?
PtichkaEL [24]

I don't see the options for an answer, so here is a list of all of the transition metals lol

  • <em>Scandium</em>
  • <em>Titanium</em>
  • <em>Vanadium</em>
  • <em>Chromium</em>
  • <em>Manganese</em>
  • <em>Iron</em>
  • <em>Cobalt</em>
  • <em>Nickel</em>
  • <em>Copper</em>
  • <em>Zinc</em>
  • <em>Yttrium</em>
  • <em>Zirconium</em>
  • <em>Niobium</em>
  • <em>Molybdenum</em>
  • <em>Technetium</em>
  • <em>Ruthenium</em>
  • <em>Rhodium</em>
  • <em>Palladium</em>
  • <em>Silver</em>
  • <em>Cadmium</em>
  • <em>Lanthanum</em>
  • <em>Hafnium</em>
  • <em>Tantalum</em>
  • <em>Tungsten</em>
  • <em>Rhenium</em>
  • <em>Osmium</em>
  • <em>Iridium</em>
  • <em>Platinum</em>
  • <em>Gold</em>
  • <em>Mercury</em>
  • <em>Actinium</em>
  • <em>Rutherfordium</em>
  • <em>Dubnium</em>
  • <em>Seaborgium</em>
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8 0
2 years ago
A 25.0 mL aliquot of 0.0680 M EDTA was added to a 59.0 mL solution containing an unknown concentration of V3 . All of the V3 pre
givi [52]

Answer:

\mathbf{0.02 M}

Explanation:

\text{So, from the given question:}

\text{EDTA will make complex with} V^{+3} \text{and the remaining EDTA will react with }Ga^{+3}

\text{Hence, the total concentration of} V^{+3} & Ga^{+3} \text{will be equivalent to EDTA concentration.}

V_{EDTA} = 25 \ mL

V_{V^{+3}} = 59.0 \ mL

V_{Ga^{+3}} = 13.0 \ mL

M_{EDTA} = 0.0680 \ M

M_{V^{+3}} = ???(unknown)

M_{Ga^{+3}} = 0.0400 \ M

V^{+3} + EDTA \to V[EDTA] + EDTA(Excess)  \to^{CoA} \ Ga[EDTA] _{complex}

M_{EDTA} \times V_{EDTA} = ( V_{V^+3}\times M_{V^{+3}}+ V_{Ga^{+3} }\times M_{Ga^{+3}}})

0.0680 \times 25 = (59\times x + 13 \times 0.040) \\ \\ 1.7 = 59x + 0.52\\ \\ 1.7 - 0.52 = 59x \\ \\ 59x = 1.18

x = \dfrac{1.18}{59}

\mathbf{x =0.02 \ M }

5 0
3 years ago
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