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Zanzabum
3 years ago
5

Convert the measurement 345.82 Kelvin to degrees Celsius.

Chemistry
2 answers:
8_murik_8 [283]3 years ago
6 0
72.67 degrees Celsius
rusak2 [61]3 years ago
6 0
72.67 degrees Celsius
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Two solids, A and B, are located in the same family on the periodic table. A sample of each is placed in a beaker of HCL. Substa
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4 0
3 years ago
Número cuántico que designa el nivel de energía en el que se localiza un electrón:
Fed [463]

Answer:

Creo que la respuesta es n. Transalation : I think the answer is N.

Explanation:

4 0
2 years ago
A+uniform+cube+is+subjected+to+volume+expansion. +if+each+side+is+decreased+by+1%,+then+bulk+strain+is
laiz [17]

A uniform cube is subjected to volume expansion. Each side gets decreased by 1%, then the bulk strain is 0.03.

<h3>What is Volume?</h3>

Volume is the space occupied by a three-dimensional object.

<h3 />

Given that, the side cube is l, then

volume V = l³

\dfrac{\Delta V}{V} = \dfrac{3D1}{1}

For change in volume

% Change in volume = 3× % change in length

= 3 × 1%

Hence, bulk strain = 0.03.



Thus, the bulk strain is 0.03.

Learn more about bulk strain

brainly.com/question/14070556

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5 0
2 years ago
A 5.76 liter sample of a gas at 22.00C mL 748 torr pressure was heated to a final volume of 17.28 liters, with the pressure rema
timama [110]

Answer:

The final temperature was 612 °C

Explanation:

Charles's law relates the volume and temperature of a certain amount of ideal gas, maintained at a constant pressure, using a constant of direct proportionality. In this law, Charles says that at constant pressure, as the temperature increases, the volume of the gas increases and as the temperature decreases, the volume of the gas decreases. That is, Charles's law is a law that says that when the amount of gas and pressure are kept constant, the ratio between volume and temperature will always have the same value:

\frac{V}{T}=k

When you want to study two different states, an initial and a final one of a gas and evaluate the change in volume as a function of temperature or vice versa, you can use the expression:

\frac{V1}{T1} =\frac{V2}{T2}

In this case:

  • V1= 5.76 L
  • T1= 22 °C= 295 °K (Being 0°C=273°K)
  • V2=17.28 L
  • T2=?

Replacing:

\frac{5.76 L}{295 K} =\frac{17.28 L}{T2}

Solving:

T2 =\frac{17.28 L}{\frac{5.76 L}{295 K}}=\frac{17.28 L*295 K}{5.76 L}

T2= 885 °K = 612 °C

<u><em>The final temperature was 612 °C</em></u>

5 0
3 years ago
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