Well, these particles happens to be small, like REALLY small. So microscopically small they aren't picked up or observed my the naked eye. also the vibrations are in an atomic scale which is also VERY tiny This goes for all solids too.
What do the bubbles indicate? <span>chemical reaction with HCl, release of H2(g)
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Where the substances are located in relation to one another on the periodic table and the activity series? <span>A is above B on the periodic table but B is above A in the activity series.
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The name of the family the substances could be in ? <span>alkaline earth, alkali metals. Either group 1 or group 2.
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<span>What substance will have a larger atomic radius? B</span>
What substance will have a larger ionization energy? A
Answer:
Creo que la respuesta es n. Transalation : I think the answer is N.
Explanation:
A uniform cube is subjected to volume expansion. Each side gets decreased by 1%, then the bulk strain is 0.03.
<h3>What is Volume?</h3>
Volume is the space occupied by a three-dimensional object.
<h3 />
Given that, the side cube is l, then
volume V = l³

For change in volume
% Change in volume = 3× % change in length
= 3 × 1%
Hence, bulk strain = 0.03.
Thus, the bulk strain is 0.03.
Learn more about bulk strain
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Answer:
The final temperature was 612 °C
Explanation:
Charles's law relates the volume and temperature of a certain amount of ideal gas, maintained at a constant pressure, using a constant of direct proportionality. In this law, Charles says that at constant pressure, as the temperature increases, the volume of the gas increases and as the temperature decreases, the volume of the gas decreases. That is, Charles's law is a law that says that when the amount of gas and pressure are kept constant, the ratio between volume and temperature will always have the same value:

When you want to study two different states, an initial and a final one of a gas and evaluate the change in volume as a function of temperature or vice versa, you can use the expression:

In this case:
- V1= 5.76 L
- T1= 22 °C= 295 °K (Being 0°C=273°K)
- V2=17.28 L
- T2=?
Replacing:

Solving:

T2= 885 °K = 612 °C
<u><em>The final temperature was 612 °C</em></u>