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3 years ago

Which ordered pair is a solution of the equation y = 3x - 3?

1 answer:

6 0

(2,3) if you plug in the Y you get 3 on the left side and then you plug in 2 and get 3*2 - 3 which is 6-3 when is 3 as well . So both values on either side are equivalent

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Two equations are listed below. Solve each equation and compare the solutions. Choose the statement that is true about both solu

enyata [817]

<span>|5x − 6| = −41 it has no solutions because module ( abs value) cannot be negative

|7x + 13| = 27 -(7x+13)=27
7x+13=27 -7x-13=27
7x=14 -7x=40
x=2 x=-40/7

check: </span>|7*(-40/7) + 13| = 27 , |-40 + 13| = 27, |-27| = 27 correct<span>

There are no statements, so I cannot choose the correct one</span>

8 0

3 years ago

A man invests $2000 in an account that pays 8.5% interest per year, compounded quarterly. (a) find the amount after 2 years? (ro

Inessa [10]

A man invests $2000 into an account that accrues 8.5% interest compounded quarterly. He made the deposit of 2 years , i.e. for 8 quarters ( or 8 compounding periods)

Amount after n years is calculated by following equation :

Amount = Principal * ( 1 + Interest rate per compounding period ) ^ no. of compounding periods

The amount in his account after 2 years = 2000 * ( 1 + 0.085/4) ^ 8

= 2000 * (1.02125 ) ^ 8

= 2000 * 1.18319

= $2366.39

4 0

3 years ago

I thought I had $35 in my bank account.

dexar [7]

your awnser will be 100 because if

6 0

3 years ago

An electronics store sells about 40 MP3 players per month for $90 each. For each $5 decrease in price, the store expects to sell

erma4kov [3.2K]

Step-by-step explanation:

Let's establish our equation first:

for every $5 decrease, there's an additional of 4 MP3 players sold.
to get the monthly revenue, we need to multiple the cost of each player to the number of units sold

$\frac{40mp3}{month} \times \frac{90dollars}{mp3} = 3600 \frac{dollars}{month}$

The equation above is for the basis month.

But the next month, we decreased the cost of mp3 player to sold 4 more units.

$\frac{(40 + 4)mp3}{month} \times \frac{(90 - 5)dollars}{mp3} = 3740 \frac{dollars}{month}$

And the next month, we decreased the cost again to gain 4 more additional units sold.

$\frac{(40 + 4x)mp3}{month} \times \frac{(90 - 5x)dollars}{mp3} = revenue per \: month$

If we substitute x with 2, we get 3840.

If we substitute x with 3, we get 3900.

If we substitute x with 4, we get 3920.

If we substitute x with 5, we get 3900.

At fifth time we decreased our price, we also got lesser revenue.

Therefore, our highest revenue would be $3,900.00 per month at our 4th price decrease with a price of $70.00.

7 0

3 years ago

PLS HELP !! I’ll appreciate it

algol13

Answer:

explanation

Step-by-step explanation:

the reason for your statement is just your explanation of why you think that.

6 0

3 years ago