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4 years ago

9

What are the two measurements necessary for calculating average speed?

2 answers:

makkiz [27]4 years ago

8 0

To calculate speed you need to know the distance traveled and the total time

IgorC [24]4 years ago

7 0

Because the average of one measurement would yield to itself, which provides nothing new to us. We need at least two for average to be purposeful.

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Which category of energy originates in the process of photosynthesis?

mojhsa [17]

Solar energy ....................

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3 years ago

Read 2 more answers

Sam's bike tire contains 15 units of air particles and has a volume of 160mL. Under these conditions the pressure reads 13 psi.

vichka [17]

Use ideal gas equation, with T constant.

pV =nRT => pV / n = RT = constant

n = K* [units of particles]

pV / [units of particles] = constant

13 psi * 160 mL / 15 units = p * 150 mL / 10 units =>

=> p = [13psi*160mL/15units]*[10units/150mL] = 9.2 psi

8 0

3 years ago

When at rest, a ruler has a length of 12.0 inches. How fast (in m/s) must the ruler fly past you in order for it to shorten to 6

PIT_PIT [208]

Answer:

2.598× $10^8 m/sec$

Explanation:

The length of the contraction is given by $l=l_0\sqrt{1-\frac{v^2}{c^2}}$ here $l_0$ is length of the ruler at rest which is given as 12 inches

l is the length of the ruler in moving condition which is given as 6 inches c is the speed of the light and v is the velocity of the ruler.

$l=l_0\sqrt{1-\frac{v^2}{c^2}}$

$\frac{l}{l_0}=\sqrt{1-\frac{v^2}{c^2}}$

$1-(\frac{l}{l_0})^2=\frac{v^2}{c^2}$

$1-(\frac{6}{12})^2=\frac{v^2}{c^2}$

$0.866=\frac{v}{c}$

$v=0.866\times 3\times 10^8=2.598\times 10^8 m/sec$

3 0

3 years ago

A grinding wheel is spinning with an initial angular velocity +ω0. When its motor is turned off at t=0, it begins to slow down w

Musya8 [376]

Answer:

Explanation:

Given

initial angular velocity is $\omega _0$

when motor is turned of it started decelerating with $-\alpha$ angular acceleration

angle turned before coming to halt

$\omega ^2-\omega _0^2=2(\alpha )\theta$

here final angular velocity is zero

$-\omega _0^2=-2\alpha \theta$

$\theta =\frac{\omega _0^2}{2\alpha }$

No of revolutions will be $N=\frac{\theta }{2\pi }$

$N=\frac{\omega _0^2}{4\pi \alpha }$

5 0

3 years ago

If 1.00 mol of an ideal monatomic gas initially at 77 K absorbs 100 J of thermal energy, what is the final temperature? Assume t

Ne4ueva [31]

Answer:

85 K

Explanation:

T₀ = initial temperature of the gas = 77 K

T = final temperature of the gas = ?

n = number of moles of monoatomic gas = 1.00 mol

R = universal gas constant = 8.314

c = heat capacity at constant volume = (1.5) R = (1.5) (8.314) = 12.5

Q = Amount of heat absorbed = 100 J

Amount of heat absorbed is given as

Q = n c (T - T₀)

100 = (1) (12.5) (T - 77)

T = 85 K

3 0

3 years ago