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frez [133]
4 years ago
9

What are the two measurements necessary for calculating average speed?

Physics
2 answers:
makkiz [27]4 years ago
8 0
To calculate speed you need to know the distance traveled and the total time
IgorC [24]4 years ago
7 0
Because the average of one measurement would yield to itself, which provides nothing new to us. We need at least two for average to be purposeful.
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Which category of energy originates in the process of photosynthesis?
mojhsa [17]
Solar energy ....................
8 0
3 years ago
Read 2 more answers
Sam's bike tire contains 15 units of air particles and has a volume of 160mL. Under these conditions the pressure reads 13 psi.
vichka [17]
Use ideal gas equation, with T constant.

pV =nRT => pV / n = RT = constant

n = K* [units of particles]

pV / [units of particles] = constant

13 psi * 160 mL / 15 units = p * 150 mL / 10 units =>

=> p = [13psi*160mL/15units]*[10units/150mL] = 9.2 psi


8 0
3 years ago
When at rest, a ruler has a length of 12.0 inches. How fast (in m/s) must the ruler fly past you in order for it to shorten to 6
PIT_PIT [208]

Answer:

2.598×10^8 m/sec

Explanation:

The length of the contraction is given by l=l_0\sqrt{1-\frac{v^2}{c^2}} here l_0 is length of the ruler at rest which is given as 12 inches

l is the length of the ruler in moving condition which is given as 6 inches c is the speed of the light and v is the velocity of the ruler.

l=l_0\sqrt{1-\frac{v^2}{c^2}}

\frac{l}{l_0}=\sqrt{1-\frac{v^2}{c^2}}

1-(\frac{l}{l_0})^2=\frac{v^2}{c^2}

1-(\frac{6}{12})^2=\frac{v^2}{c^2}

0.866=\frac{v}{c}

v=0.866\times 3\times 10^8=2.598\times 10^8 m/sec

3 0
3 years ago
A grinding wheel is spinning with an initial angular velocity +ω0. When its motor is turned off at t=0, it begins to slow down w
Musya8 [376]

Answer:

Explanation:

Given

initial angular velocity is \omega _0

when motor is turned of it started decelerating with -\alpha  angular acceleration

angle turned before coming to halt

\omega ^2-\omega _0^2=2(\alpha )\theta

here final angular velocity is zero

-\omega _0^2=-2\alpha \theta

\theta =\frac{\omega _0^2}{2\alpha }

No of revolutions will be N=\frac{\theta }{2\pi }

N=\frac{\omega _0^2}{4\pi \alpha }

5 0
3 years ago
If 1.00 mol of an ideal monatomic gas initially at 77 K absorbs 100 J of thermal energy, what is the final temperature? Assume t
Ne4ueva [31]

Answer:

85 K

Explanation:

T₀ = initial temperature of the gas = 77 K

T = final temperature of the gas = ?

n = number of moles of monoatomic gas = 1.00 mol

R = universal gas constant = 8.314

c = heat capacity at constant volume = (1.5) R = (1.5) (8.314) = 12.5

Q = Amount of heat absorbed = 100 J

Amount of heat absorbed is given as

Q = n c (T - T₀)

100 = (1) (12.5) (T - 77)

T = 85 K

3 0
3 years ago
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