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AveGali [126]
3 years ago
10

Networks that are designed to connect similar computers that share data and software with each other are called: client/server n

etworks peer-to-peer networks host networks client networks local area networks?
Physics
1 answer:
aev [14]3 years ago
8 0

peer-to-peer networks

Explanation:

Networks designed to connects similar computers that shares data and software with each other are called peer-to-peer networks.

These networks are closely around and do not rely on information passing through a central data point.

  • In a peer to peer connection, the computers have direct access to one another.
  • The computers over the network becomes both client and server.

learn more:

Machines on public network brainly.com/question/10338479

#learnwithBrainly

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4 years ago
A current of 0.8 A flows through the motor for 3 minutes. Calculate the total charge in this time.
mixas84 [53]

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The given terms are :

Current = 0.8 Amperes

Time = 3 minutes = 3 × 60 = 180 seconds

we know that,

  • current =  \dfrac{charge}{time}

now, let's solve for charge (q) :

  • 0.8 =  \dfrac{q}{180}

  • q = 180 \times 0.8

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Total Charge (q) = 144 Coulombs

7 0
3 years ago
Common transparent tape becomes charged when pulled from a dispenser. If one piece is placed above another, the repulsice force
Dmitriy789 [7]

Answer:

Q = 1.095 x 10^-9 C

Let the force experienced by the top piece of tape be F

F = kQ²/r²

r = distance between the two pieces tape = 1.00cm = 1.00 x 10^ -2 m

1/4(pi)*Eo = k = 8.99 x 10^9 Nm²/C²

The electric force of repulsion between the two charges and the weight of the top piece of tape are equal so

F = kQ²/r² = mg

Where m is the mass of the top piece of tape and g is the acceleration due to gravity

On re-arranging the equation above,

Q² = mgr²/k

Q² = ((11.0 x 10^-6) x 9.8 x (1.00x10^-2)²)/(8.99 x 10^9)

Q = 1.095x10^-9 C

Explanation:

The charge Q on both pieces of tape are equal and both act with a force of repulsion on each other.

The force of repulsion between both tapes pushes the top piece of tape upwards. The weight of the top piece of tape acts vertically downward. Since the top tape is in a position of equilibrium, the two forces acting on the top piece of tape must be equal to each other. This assumption is backed up by newton's first law of motion which states that the summation of all forces acting on a body at rest must be equal to zero. That is

Fe (electric force) - Fg (gravitational force) = 0

Fe = Fg

kQ²/r² = mg

On substituting the respective values for all variables except Q and rearranging the equation Q = 1.09 x 10^-9

6 0
4 years ago
A 40-kg worker climbs a ladder upwards for 15m. What work was done during their climb upwards?
Bingel [31]

Answer:

Explanation:

The work increased the potential energy

W = PE = mgh = 40(9.8)(15) = 5880 J(oules)

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2 years ago
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Sergeeva-Olga [200]

Answer:

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