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AveGali [126]
3 years ago
10

Networks that are designed to connect similar computers that share data and software with each other are called: client/server n

etworks peer-to-peer networks host networks client networks local area networks?
Physics
1 answer:
aev [14]3 years ago
8 0

peer-to-peer networks

Explanation:

Networks designed to connects similar computers that shares data and software with each other are called peer-to-peer networks.

These networks are closely around and do not rely on information passing through a central data point.

  • In a peer to peer connection, the computers have direct access to one another.
  • The computers over the network becomes both client and server.

learn more:

Machines on public network brainly.com/question/10338479

#learnwithBrainly

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The air temperature in a 28 in.3 container with a free sliding piston is initially measured at 45 °
sergiy2304 [10]

To solve this we assume that the gas inside is an ideal gas. Then, we can use the ideal gas equation which is expressed as PV = nRT. At a constant pressure and number of moles of the gas the ratio T/V is equal to some constant. At another set of condition of temperature, the constant is still the same. Calculations are as follows:

T1 / V1 = T2 / V2

V2 = T2 x V1 / T1

V2 = 659.7 x 28 / 504.7

<span>V2 = 36.60 in^3</span>

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Consider the same 70kg/686N student on the surface on another planet from the table above: Jupiter. Tompared to the gravitationa
Yuliya22 [10]

Answer:

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Explanation:

6 0
3 years ago
What must be the pressure difference between the two ends of a 2.6 km section of pipe, 36 cm in diameter, if it is to transport
ad-work [718]

Answer: 1.13(10)^{3} Pa

Explanation:

This problem can be solved by the following equation:

\Delta P=\frac{8 \eta L Q}{\pi r^{4}}

Where:

\Delta P is the pressure difference between the two ends of the pipe

\eta=0.20 Pa.s is the viscosity of oil

L=2.6 km=2600 m is the length of the pipe

Q=900 \frac{cm^{3}}{s} \frac{1 m^{3}}{(100 cm)^{3}}=0.0009 \frac{m^{3}}{s} is the Rate of flow of the fluid

d=36 cm=0.36 m is the diameter of the pipe

r=\frac{d}{2}=0.18 m is the radius of the pipe

Soving for \Delta P:

\Delta P=\frac{8 (0.20 Pa.s)(2600 m)(0.0009 \frac{m^{3}}{s})}{\pi (0.18 m)^{4}}

Finally:

\Delta P=1135.26 Pa \approx 1.13(10)^{3} Pa

7 0
3 years ago
X + 10 times X = 50 what is the answer
tia_tia [17]

Answer:

4.54

Explanation:

X+10X=50

11X=50

X=4.54#

<h2>please follow me...</h2>
3 0
3 years ago
If you increase the size of the resistor and keep the voltage the same, what will happen to the current
Grace [21]

Answer:

If voltage is kept constant across the resistor itself, it' current will reduce. If the resistance is part of oscillator circuit, frequency response will change. If it is in series with capacitor or inductor, it will change the damping effect.

Explanation:

8 0
3 years ago
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