Answer: Option (c) is the correct answer.
Explanation:
Atomic number of sodium is 11 and its electronic configuration is 
. When sodium loses one electron then it will attain +1 charge and its electronic configuration will be as follows.
: 
Atomic number of fluorine is 9 and its electronic configuration is 
. When fluorine gains an electron then it acquires -1 charge and its electronic configuration is as follows.
:
Atomic number of aluminium is 13 and its electronic configuration is 
. When aluminium loses its valence electrons then it acquires +3 charge and its electronic configuration is as follows.
:
Thus, we can conclude that the listing for aluminum is correct.
During all chemical reactions, the mass of the products is never equal to the mass of the reactants.
- FALSE
Mass is sometimes lost in chemical reactions.
- FALSE
The Law of Conservation of Mass states that mass is not conserved.
- FALSE
The correct answer is D . Milk
Answer:
0.683 moles of the gas are required
Explanation:
Avogadro's law relates the moles of a gas with its volume. The volume of a gas is directely proportional to its moles when temperature and pressure of the gas remains constant. The law is:
V₁n₂ = V₂n₁
<em>Where V is volume and n are moles of 1, initial state and 2, final state of the gas.</em>
<em />
Computing the values of the problem:
1.50Ln₂ = 5L*0.205mol
n₂ = 0.683 moles of the gas are required
<em />
Answer:
0.37 g
Explanation:
The molecular weight for Glycerol = 92
Number of Carbon atoms in glycerol (x) 
= 3
Molecular weight of the Biomass ( Klebsiella aerogenes )
= 
= 
= 26.1
From the molecular weight of the Biomass, we can deduce the Degree of reduction for the substrate(glycerol denoted as 
) as follows:
= (4×1)+(1×1.73)-(2×0.43)-(3×0.24)
= 4.15
Given that the yield of the Biomass = 0.40 g
However;
C = 
C = 
C = 1.41 g
Now , the oxygen requirement can be calculated as:
= 
= 
= 2.1 g/mol
Hence, we can say that the needed oxygen = 2.1 g/mol of the substrate consumed.
Now converting it to mass terms; we have:
= 
= 
= 0.3652 g
≅ 0.37 g
∴ The oxygen requirement for this culture in mass terms = 0.37 g
