The mole ratio of acetic acid to water in 100 g of vinegar is 0.015 : 0.985.
<h3>What is the mole ratio of acetic acid to water in 100 g of vinegar?</h3>
The mole ratio of acetic acid to water in 100 g of vinegar is determined from their percentage composition.
The percentage composition of acetic acid and water in vinegar is 5% acetic acid and 95% water.
In 100 g of vinegar, there are 5 g of acetic acid and 5 g of water.
Moles = mass/molar mass
molar mass of acetic acid = 62 g/mol
molar mass of water = 18 g/mol
moles of vinegar = 5/62 = 0.08
moles of water = 95/18 = 5.28
total moles = 5.36
Mole ratio of vinegar to water = 0.08/5.36 : 5.28/5.36
Mole ratio of vinegar to water = 0.015 : 0.985
In conclusion, the mole ratio is determined from the percentage composition of acetic acid and water in vinegar.
Learn more about mole ratio at: brainly.com/question/19099163
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Answer: Option (C) is the correct answer.
Explanation:
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Therefore, when a person graduated from a college with a degree in horticulture then it means he has obtained enough knowledge about how to grow plants, fruits or vegetables in the best way possible.
Thus, Vincent who also graduated in horticulture cannot accurately tell about human psychology.
Hence, we can conclude that the statement this claim may not be accurate because the blog is produced by someone who is not an expert in the field of human psychology.
hey mate here is ur answer
solution
mass{m}=3 gram
=3/1000
volume{v}=16cm
=16/100
density=m/v
=3/1000÷16/100
=3/160
=0.01875kg/m3