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3 years ago

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Which sample has particles with the lowest average kinetic energy?

2 answers:

Thepotemich [5.8K]3 years ago

7 0

Answer : Option 4) 9.0 g of $I_{2}$ at 20°C

Explanation : Usually the average kinetic energy depends upon the state of the matter. Considering about the iodine at lower temperature the kinetic energy is found to be low. Whereas at higher temperature has higher kinetic energy value.

From the kinetic energy equation it can be easily related that K.E. is directly proportional to the temperature.

Refer the attached image for the relationship of temperature with kinetic energy.

Anastasy [175]3 years ago

3 0

The question asks average kinetic energy. So it is only related with the temperature. The higher temperature is, the higher kinetic energy is. So the answer is (4).

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nata0808 [166]

Answer:

C. They vibrate faster.

Explanation:

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3 years ago

Read 2 more answers

A 0.1873 g sample of a pure, solid acid, H2X (a diprotic acid) was dissolved in water and titrated with 0.1052 M NaOH solution.

puteri [66]

Answer:

We need 41.8 mL of NaOH

Explanation:

<u>Step 1:</u> Data given

Mass of H2X = 0.1873 grams

Molarity of NaOH solution = 0.1052 M

Molar mass of H2X = 85.00 g/mol

<u>Step 2</u>: The balanced equation

H2X (aq) +2 NaOH (aq) → Na2X (aq) + 2H2O(l)

<u>Step 3:</u> Calculate moles of H2X

Moles H2X = mass H2X / Molar mass H2X

Moles H2X = 0.1873 grams / 85.00 g/mol

Moles H2X = 0.0022 moles

<u>Step 4:</u> Calculate moles of NaOH

For 1 mol H2X we need 2 moles NaOH to produce 1 mole of Na2X and 2 moles of H2O

For 0.0022 moles of H2X we need 0.0044 moles of NaOH

<u />

<u>Step 5</u>: Calculate volume of NaOH

Volume of NaOH = moles of NaOH / molarity of NaOH

Volume of NaOH = 0.0044 moles / 0.1052 M

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3 years ago

The 1995 Nobel Prize in Chemistry was shared by Paul Crutzen, F. Sherwood Rowland, and Mario Molina for their work concerning th

horrorfan [7]

Answer:

The enthalpy of reaction for the reaction of chlorine with ozone is -162.5 kJ.

Explanation:

$ClO ( g ) + O_3 ( g )\rightarrow Cl ( g ) + 2 O_2 ( g ),\Delta H^o_{1,rxn} =-122.8 kJ$ ..[1]

$2 O_3 ( g )\rightarrow 3O_2 ( g ),\Delta H^o_{2,rxn} = -285.3 kJ$ ..[2]

$O_3(g) + Cl(g)\rightarrow ClO (g)+O_2(g),\Delta H^o_{3,rxn}=?$ ..[3]

The enthalpy of reaction for the reaction of chlorine with ozone can be calculated by using Hess's law:

[2] - [1] = [3]

$\Delta H^o_{3,rxn}=\Delta H^o_{2,rxn}-\Delta H^o_{1,rxn}$

$=-285.3 kJ-(-122.8 kJ)=162.5 kJ$

The enthalpy of reaction for the reaction of chlorine with ozone is -162.5 kJ.

8 0

3 years ago

Is my answer correct

Cerrena [4.2K]

Yes it’s correct.
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3 years ago

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GaryK [48]

The mass should be equal to 28800 grams

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