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inna [77]
2 years ago
9

Which sample has particles with the lowest average kinetic energy?

Chemistry
2 answers:
Thepotemich [5.8K]2 years ago
7 0

Answer : Option 4) 9.0 g of I_{2} at 20°C


Explanation : Usually the average kinetic energy depends upon the state of the matter. Considering about the iodine at lower temperature the kinetic energy is found to be low. Whereas at higher temperature has higher kinetic energy value.


From the kinetic energy equation it can be easily related that K.E. is directly proportional to the temperature.


Refer the attached image for the relationship of temperature with kinetic energy.

Anastasy [175]2 years ago
3 0
The question asks average kinetic energy. So it is only related with the temperature. The higher temperature is, the higher kinetic energy is. So the answer is (4).
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A chemist measures the enthalpy change ?H during the following reaction: Fe (s) + 2HCl (g) ? FeCl2 (s) + H2 (g) =?H?157.kJ Use t
erik [133]

Correct Question:

A chemist measures the enthalpy change ΔH during the following reaction: Fe(s) + 2HCl(g)-->FeCl2(s) + H2 ΔH=-157.0 kJ. Use this information to complete the table below. Round each of your answers to the nearest kJ/mol

Answer:

-314 kJ

+628 kJ

+157 kJ

Explanation:

The enthalpy change of a reaction measures the amount of heat that is lost or gained by it. If ΔH >0 the heat is gained, and the reaction is called endothermic, if ΔH<0, the heat is lost, and the reaction is called exothermic.

If the reaction is inverted, the value of ΔH is inverted too (the opposite endothermic reaction is exothermic), and if the reaction is multiplied by a constant, ΔH will be multiplied by it too.

1) 2Fe(s) + 4HCl --> 2FeCl2(s) + 2H2(g)

This reaction is the product of the given reaction by 2, so

ΔH = 2*(-157) = -314 kJ

2) 4FeCl2(s) + 4H2(g) --> 4Fe(s) + 8HCl(g)

This reaction is the inverted reaction given multiplied by 4, so

ΔH = 4*(157) = +628 kJ

3) FeCl2(s) + H2(g) --> Fe(s) + 2HCl

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Answer:

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Explanation:

Step 1: Given and required data

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Step 2: Calculate the moles (n) of ammonia (solute)

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