Explanation:
It is given that initially pressure of ideal gas is 4.00 atm and its temperature is 350 K. Let us assume that the final pressure is 
and final temperature is 
.
(a) We know that for a monoatomic gas, value of 
is \frac{5}{3}[/tex].
And, in case of adiabatic process,
= constant
also, PV = nRT
So, here 
= 350 K, 
, and 
Hence, 
= 267 K
Also, 
= 4.0 atm, , and
= 2.04 atm
Hence, for monoatomic gas final pressure is 2.04 atm and final temperature is 267 K.
(b) For diatomic gas, value of is \frac{7}{5}[/tex].
As, = constant
also, PV = nRT
= 350 K, , and
= 289 K
And, = 4.0 atm, , and
= 2.27 atm
Hence, for diatomic gas final pressure is 2.27 atm and final temperature is 289 K.
Answer:
A
Explanation:
Initial gravitational energy = final kinetic energy + heat
mgh = KE + Q
(50 kg) (9.81 m/s²) h = 78400 J + 884000 J
h = 1960 meters
Answer:
pahingi po ng pic pls para masagutang kopo iyan
Answer:
685.6 J
Explanation:
The latent heat of vaporization of ammonia is
L = 1371.2 kJ/kg
mass of ammonia, m = 0.0005 Kg
Heat = mass x latent heat of vaporization
H = 0.0005 x 1371.2
H = 0.686 kJ
H = 685.6 J
Thus, the amount of heat required to vaporize the ammonia is 685.6 J.
Answer:
4.3 m/s
Explanation:
Using conservation of momentum, assume that the collision is elastic and that the 3.0 g ball stuck with the carton
3.0 g = 3 / 1000 = 0.003 kg = m₁
40 g = 40 / 1000 = 0.04 kg = m₂, u₂ = 0 since the body is stationary and v = 0.3m/s
m₁u₁ + m₂u₂ = v ( m₁ + m₂)
0.003 u₁ = 0.30 ( 0.003 + 0.04) = 0.0129
u₁ = 0.0129 / 0.003 = 4.3 m/s
