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4 years ago

Which of the following is a conductor for electricity?

Physics

1 answer:

zhannawk [14.2K]4 years ago

4 0

It would be wool. (: Like rubbing your feet against carpet ? same affect. (:
Good luck, rockstar, and I hope you pass!

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A 65 N boy sits on a sled weighing 52 N on a horizontal surface. The coefficient of friction between the sled and the snow is 0.

pogonyaev

Answer:

1.40 N

Explanation:

The magnitude of the frictional force is given by:

$F=\mu N$

where

$\mu$ is the coefficient of friction

N is the magnitude of the normal reaction

The coefficient of friction for this problem is $\mu=0.012$ . The magnitude of the normal reaction is equal to the combined weight of the boy and the sled, because the surface is horizontal, so

$N=65 N+52 N=117 N$

Therefore, the frictional force is

$F=\mu N=(0.012)(117 N)=1.40 N$

3 0

3 years ago

Need help on this on 6 and 7

Paladinen [302]

6) the last one
7) black t-shirt

7 0

4 years ago

April and Alex are saving money to buy new phones. Each friend starts with some money and saves a specific amount each week.

qwelly [4]

First thing to note is that we are on week 0, when they start saving:

The equation for Alex is:

y=20x + 125

Know that we are on week 0, and x is our weeks, that makes our equation:

y=20(0) + 125

Which means it's really:

y=125

That means that the first one is E. 125

For the second, it shows our week 0, which is at 100.

That means that the second one is I. 100

Hope this helps!

5 0

4 years ago

Read 2 more answers

According to Boyles’ law, PV = constant. If a graph is plotted with the pressure P against the volume V, the graph would be a(n)

Hunter-Best [27]

Answer:

C. hyperbola

Explanation:

From Boyle's law:

PV = k, where k is a constant

Solving for P:

P = k / V

At first glance, this equation doesn't fit any of the options. But when you graph it, you can see that it's actually a rotated hyperbola.

4 0

3 years ago

Read 2 more answers

A nichrome wire and an aluminum wire, each with the same initial resistance, have the same change in resistance when heated sepa

Svetach [21]

Answer:

The ratio of temperature change of nichrome wire to the temperature change of aluminum wire is found to be 9.75

Explanation:

The change in resistances and initial resistances of the wires are:

Change in Resistance of Nichrome Wire = ΔR₁

Change in Resistance of Aluminum Wire = ΔR₂

Initial Resistance of Nichrome Wire = R₁

Initial Resistance of Aluminum Wire = R₂

Also, it is given that the change in resistance and initial resistance of both wires is equal. Therefore,

ΔR₁ = ΔR₂ ---------- eqn (1)

R₁ = R₂ ---------- eqn (2)

The change in Resistance due to temperature is given by formula:

ΔR = R α ΔT

Therefore, eqn (1) becomes:

R₁ α₁ ΔT₁ = R₂ α₂ ΔT₂

using eqn (2):

α₁ ΔT₁ = α₂ ΔT₂

ΔT₁/ΔT₂ = α₂/α₁

where,

α₁ = Temperature coefficient of resistance of nichrome = 0.4 x 10⁻³ °C⁻¹

α₂ = Temperature coefficient of resistance of aluminum = 3.9 x 10⁻³ °C⁻¹

Therefore,

ΔT₁/ΔT₂ = (3.9 x 10⁻³ °C⁻¹)/(0.4 x 10⁻³ °C⁻¹)

ΔT₁/ΔT₂ = 9.75

6 0

4 years ago