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gogolik [260]
3 years ago
13

When air expands adiabatically (without gaining or losing heat), its pressure P and volume V are related by the equation PV1.4=C

where C is a constant. Suppose that at a certain instant the volume is 420 cubic centimeters and the pressure is 99 kPa and is decreasing at a rate of 7 kPa/minute. At what rate in cubic centimeters per minute is the volume increasing at this instant?
Physics
2 answers:
DiKsa [7]3 years ago
5 0

Answer:

\frac{dV}{dt}=21.21cm^3/min

Explanation:

We are given that

PV^{1.4}=C

Where C=Constant

\frac{dP}{dt}=-7KPa/minute

V=420 cubic cm and P=99KPa

We have to find the rate at which the  volume increasing at this instant.

Differentiate w.r.t t

V^{1.4}\frac{dP}{dt}+1.4V^{0.4}P\frac{dV}{dt}=0

Substitute the values

(420)^{1.4}\times (-7)+1.4(420)^{0.4}(99)\frac{dV}{dt}=0

1.4(420)^{0.4}(99)\frac{dV}{dt}=(420)^{1.4}\times (7)

\frac{dV}{dt}=\frac{(420)^{1.4}\times (7)}{1.4(420)^{0.4}(99)}

\frac{dV}{dt}=21.21cm^3/min

kupik [55]3 years ago
3 0

Answer:

\dot V=2786.52~cm^3/min

Explanation:

Given:

initial pressure during adiabatic expansion of air, P_1=99~kPa

initial volume during the process, V_1=420~cm^3

The adiabatic process is governed by the relation PV^{1.4}=C ; where C is a constant.

Rate of decrease in pressure, \dot P=7~kPa/min

Then the rate of change in volume, \dot V can be determined as:

P_1.V_1^{1.4}=\dot P.\dot V^{1.4}

99\times 420^{1.4}=7\times V^{1.4}

\dot V=2786.52~cm^3/min

\because P\propto\frac{1}{V}

\therefore The rate of change in volume will be increasing.

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stepan [7]

Answer:

Newton's law of inertia - His first law states that every object remains at rest or in uniform motion in a straight line unless compelled to change its state by the action of an external force. ... This is the first part cited in Newton's first law; "there is no net force on the airplane and it travels at a constant velocity in a straight line."

Newton's law of acceleration -  "a net external force changes the velocity of the object. The drag of the aircraft depends on the square of the velocity. So the drag increases with increased velocity."

Newton's law of Action/Reaction - "As a plane flies, the force of the air hitting the plane is always equal and opposite to the force of the plane pushing against the air. The force generated by the engine pushes against air while the air pushes back with an equal and opposite force."

Hope this helps! god bless :)

Please give me brainliest!

5 0
3 years ago
A seesaw is 4.0m long with a pivot at its midpoint. A boy who weighs 400N sits at a distance of 1.5m from the pivot. His sister
bezimeni [28]

Answer:

the girl must sit 2 cm from the pivot at the opposite end of the seesaw.

Explanation:

Given;

length of the seesaw, L = 4.0 m

weight of the boy, W₁ = 400 N

position of the boy from the pivot, d₁ = 1.5 m

weight of her sister, W₂ = 300 N

First, make a sketch of this information given;

                 0---0.5m---------------------Δ--------------------------4m

                         ↓<--------1.5m-------> <---------x--------->↓

                        400 N                                          300N

Apply the principle of moment about the pivot, to determine the value of x;

Sum of anticlockwise moment = sum of clockwise moment

400(1.5) = 300(x)

600 = 300x

x = 600/300

x = 2 cm

Thus, the girl must sit 2 cm from the pivot at the opposite end of the seesaw.

8 0
3 years ago
Two hypothetical discoveries in Part A deal with moons that, like Earth's moon, are relatively large compared to their planets.
ser-zykov [4K]

Answer:

Explanation:

Solution:

- Finding large moons comparable in size to their planets result from impacts of two astro-bodies. The probability of such an event occurring is very rare.

- Even at the best luck, one moon can be made from the result of giant impact. While the probability of 6 planets having moons of comparable sizes is close to impossible.

6 0
3 years ago
Weak magnetic fields can be measured at the surface of the brain. Although the currents causing these fields are quite complicat
STALIN [3.7K]

To develop this problem it is necessary to apply the concepts related to a magnetic field in spheres.

By definition we know that the magnetic field in a sphere can be described as

B = \frac{\mu_0}{2}\frac{Ia^2}{(z^2+a^2)^{3/2}}

Where,

a = Radius

z = Distance to the magnetic field

I = Current

\mu_0 = Permeability constant in free space

Our values are given as

D=2a = 16cm \rightarrow diameter of the sphere then,

a = 0.08m

Thus z = a

B = \frac{\mu_0}{2}\frac{Ia^2}{(a^2+a^2)^{3/2}}

B = \frac{\mu_0I}{2(2^{3/2})a}

B = \frac{\mu_0 I}{2^{5/2}a}

Re-arrange to find I,

I = \frac{2^{5/2}Ba}{\mu_0}

I = \frac{2^{5/2}(3*10^{-12})(8*10^{-2})}{4\pi*10^{-7}}

I = 1.08*10^{-6}A

Therefore the current at the pole of this sphere is 1.08*10^{-6}A

5 0
3 years ago
Estimate and determine the order of magnitude of the circumference of the Earth in miles and the speed of a sailboat in miles pe
solmaris [256]

Answer:

= 1000 hours

Explanation:

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distance = speed × time

10⁴ = 10¹  × t

t = 10⁴ / 10¹

t = 10³

= 1000 hours

4 0
3 years ago
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