Question

[16]. A 3.0 L container holds a sample of hydrogen gas at 150 kPa. If the pressure increases to 2 atm and the temperature remains constant, what will the volume be?
a). 4.50 L
x b). 2.25 L
c). 0.44 L
d). 0.22 L

Answer 1

First, let's convert atm to kPa: 
2atm x 101.33kPa = 202.66kPa

Now, to find the pressure, you would have to use Boyle's Law: (P1V1)=(P2V2)
(150kPa x 3.0L) =  (202.66kPa x V2)
V2= (150kPa x 3.0L)/202.66kPa
V2=2.2L, B is your answer. This makes because volume and pressure have an inverse relationship, so since pressure increased volume should decrease.