Clearly, moving the object closer<span> to the </span>lens<span> makes the image become both larger and further away. As you </span>move<span> the </span>object closer<span> and </span>closer<span> to the focal point, the image will become further and further away. ... As expected the image </span>moves<span> further away and becomes much bigger than the </span>object<span>.
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Answer:
One million of silver atoms weigh 1.79 xx 10^(-16)g. Calculate the atomic mass of silver. Atomic mass of silver =107.8g=107.8u
Answer:
Na: 1s2 2s2 2p6 3s1
Na+: 1s2 2s2 2p6
Na+ electronic configuration resemble that of Neon( 1s2 2s2 2p6)
In general, the electronic configuration of alkali metals ions resemble that of the group zero (noble gas)
<span>Answer:
A 1.00 L solution containing 3.00x10^-4 M Cu(NO3)2 and 2.40x10^-3 M ethylenediamine (en).
contains
0.000300 moles of Cu(NO3)2 and 0.00240 moles of ethylenediamine
by the formula Cu(en)2^2+
0.000300 moles of Cu(NO3)2 reacts with twice as many moles of en = 0.000600 mol of en
so, 0.00240 moles of ethylenediamine - 0.000600 mol of en reacted = 0.00180 mol en remains
by the formula Cu(en)2^2+
0.000300 moles of Cu(NO3)2 reacts to form an equal 0.000300 moles of Cu(en)2^2+
Kf for Cu(en)2^2+ is 1x10^20.
so
1 Cu+2 & 2 en --> Cu(en)2^2+
Kf = [Cu(en)2^2+] / [Cu+2] [en]^2
1x10^20. = [0.000300] / [Cu+2] [0.00180 ]^2
[Cu+2] = [0.000300] / (1x10^20) (3.24 e-6)
Cu+2 = 9.26 e-19 Molar
since your Kf has only 1 sig fig, you might be expected to round that off to 9 X 10^-19 Molar Cu+2</span>
Primary producers i believe
