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4 years ago

3= whole number and a power of 10

2 answers:

6 0

Write it out:-

3^10

Solve;-

3^10 = 3 × 3 × 3 × 3 × 3 × 3 × 3 × 3 × 3 × 3 = <span>59049
3^10 =</span><span>59049</span>

strojnjashka [21]4 years ago

5 0

3 × 3 × 3 × 3 × 3 × 3 × 3 × 3 × 3 × 3 = <span>59049
3 = whole number and a power of 10 = </span><span>59049</span>

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What is the anser to the equation 2^{2x+2} = 2^{3x}

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Using the formula for the area and circumference of a circle, we have the following answers:

1. radius = 2 in. (given)

Diameter = 4 in.

Circumference = 12.56 in.

Area = 12.56 in.²

2. radius = 10 in.

Diameter = 20 in. (given)

Circumference = 62.8 in.

Area = 314 in.²

3. radius = 5 in.

Diameter = 10 in. (given)

Circumference = 31.4 in.

Area = 78.5 in.²

4. radius = 20 in.

Diameter = 40 in. (given)

Circumference = 125.6 in.

Area = 1,256 in.²

5. radius = 18 in. (given)

Diameter = 36 in.

Circumference = 113.04 in.

Area = 1,017.36 in.²

6. radius = 8 in. (given)

Diameter = 16 in.

Circumference = 50.24 in.

Area = 200.96 in.²

7. radius = 12 in. (given)

Diameter = 24 in.

Circumference = 75.36 in.

Area = 452.16 in.²

8. radius = 16 in.

Diameter = 32 in. (given)

Circumference = 100.48 in.

Area = 803.84 in.²

9. radius = 15 in. (given)

Diameter = 30 in.

Circumference = 94.2 in.

Area = 706.5 in.²

<h3>What is the Area and Circumference of a Circle?</h3>

Area of a circle = πr²
Circumference of a circle = 2πr or πd, where r is radius and d is diameter.

1. radius = 2 in. (given)

Diameter = 2(2) = 4 in.

Circumference = πd = π(4) = 12.56 in.

Area = πr² = π(2²) = 12.56 in.²

2. radius = 1/2(20) = 10 in.

Diameter = 20 in. (given)

Circumference = πd = π(20) = 62.8 in.

Area = πr² = π(10²) = 314 in.²

3. radius = 1/2(10) = 5 in.

Diameter = 10 in. (given)

Circumference = πd = π(10) = 31.4 in.

Area = πr² = π(5²) = 78.5 in.²

4. radius = 1/2(40) = 20 in.

Diameter = 40 in. (given)

Circumference = πd = π(40) = 125.6 in.

Area = πr² = π(20²) = 1,256 in.²

5. radius = 18 in. (given)

Diameter = 2(18) = 36 in.

Circumference = πd = π(36) = 113.04 in.

Area = πr² = π(18²) = 1,017.36 in.²

6. radius = 8 in. (given)

Diameter = 2(8) = 16 in.

Circumference = πd = π(16) = 50.24 in.

Area = πr² = π(8²) = 200.96 in.²

7. radius = 12 in. (given)

Diameter = 2(12) = 24 in.

Circumference = πd = π(24) = 75.36 in.

Area = πr² = π(12²) = 452.16 in.²

8. radius = 1/2(32) = 16 in.

Diameter = 32 in. (given)

Circumference = πd = π(32) = 100.48 in.

Area = πr² = π(16²) = 803.84 in.²

9. radius = 15 in. (given)

Diameter = 2(15) = 30 in.

Circumference = πd = π(30) = 94.2 in.

Area = πr² = π(15²) = 706.5 in.²

Learn more about area and circumference of circle on:

brainly.com/question/402655

7 0

2 years ago