Answer:
1. Alkali metals (group 1)
2. halogens (Group 17)
3. noble gasses (group 18)
Explanation:
1. alkali metals only have one valence electron meaning that they really want to lose that one valence electron to get a full octet.
2. halogens have 7 valence electrons meaning that they just need to gain 1 to get a full octet.
3. Nobel gasses already have a full octet meaning that they don't want to react. (atoms only react to get a full octet)
I hope this helps. Let me know if anything is unclear.
There are two isotopes of uranium abundant in nature
U235 and U238
As given that the sample has average molar mass of 237.482 amu
Let the amount of U235 in 100g sample = x
the amount of U238 in 100 g sample = 100-x
the average molar mass = [235(x) + 238 (100-x)] / 100
237.482 = [235(x) + 238 (100-x)] / 100
237.482 X 100 = [235(x) + 238 (100-x)]
23748.2 = 235 x + 23800 - 238x
51.8 = 3x
x = 17.27 g
So percentage of U-235 = 17.27 %
4HCl + MnO₂ → MnCl₂ + 2H₂O + Cl₂
2Cl⁻ → Cl₂ + 2e⁻
MnO₂ + 4H⁺ + 2e⁻ → Mn²⁺ + 2H₂O
2Cl⁻ + MnO₂ + 4H⁺ → Cl₂ + Mn²⁺ + 2H₂O
time travel is the best option
Answer:
Explanation: Avogadro number,N, = 6.02214076*10^23per mole —> 22.71L
—>( 7.41*10^26/N)*22.71 = 22.79*10^3 = 22,790L
