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Nataly_w [17]
3 years ago
8

Which line of defense includes active immunity?

Chemistry
2 answers:
PSYCHO15rus [73]3 years ago
7 0

Answer:

B is the answer.

Explanation:

Can i have Brainliest

NeX [460]3 years ago
6 0

Answer:

Second line of deffence is the correct answer I just got it correct from my exam!

Explanation:

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Im hvaing a hard time getting the right answer
Tanya [424]

Answer:

V=23.9mL

Explanation:

Hello!

In this case for the solution you are given, we first use the mass to compute the moles of CuNO3:

n=2.49g*\frac{1mol}{125.55 g}=0.0198mol

Next, knowing that the molarity has units of moles over liters, we can solve for volume as follows:

M=\frac{n}{V}\\\\V=\frac{n}{M}

By plugging in the moles and molarity, we obtain:

V=\frac{0.0198mol}{0.830mol/L}=0.0239L

Which in mL is:

V=0.0239L*\frac{1000mL}{1L}\\\\V=23.9mL

Best regards!

6 0
3 years ago
I would like some assistance
charle [14.2K]

Answer:

#2.

Explanation:

Look at the charges. Both are positive, therefore both are cations.

6 0
2 years ago
A student had a sample of pure water, and added an unknown substance to it. The student noticed that the hydroxide ion concentra
steposvetlana [31]
The answer is A it's a basic because once you add another substance to a neutral it either becomes acidic or basic. this one becomes basic because the hydroxide ion concentrate increased.
6 0
3 years ago
Read 2 more answers
Predict what kind of energy process happens when Lye, NaOH(s) is put in water and the water gets hot
Grace [21]
What happens is that the sodium solution when put in water reacts and creates thermal energy .
3 0
3 years ago
Read 2 more answers
Use calc to determine whether it is possible to remove 99.99% Cu2 by converting it to Cu(s) in a solution mixture containing 0.1
inessss [21]

Answer:

it is possible to remove 99.99% Cu2 by converting it to Cu(s)

Explanation:

So, from the question/problem above we are given the following ionic or REDOX equations of reactions;

Cu2+ + 2e- <--------------------------------------------------------------> Cu (s) Eo= 0.339 V

Sn2+ + 2e- <---------------------------------------------------------------> Sn (s) Eo= -0.141 V

In order to convert 99.99% Cu2 into Cu(s), the equation of reaction given below is needed:

Cu²⁺ + Sn ----------------------------------------------------------------------------> Cu + Sn²⁺.

Therefore, E°[overall] = 0.339 - [-0.141] = 0.48 V.

Therefore, the change in Gibbs' free energy, ΔG° = - nFE°. Where E° = O.48V, n= 2 and F = 96500 C.

Thus, ΔG° = - 92640.

This is less than zero[0]. Therefore,  it is possible to remove 99.99% Cu2 by converting it to Cu(s) because the reaction is a spontaneous reaction.  

7 0
3 years ago
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