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Answer:
The more worn-out the rock is, the older it is
Explanation:
Hello,
The different layers a rock has could be useful to date it, as long as the deepest layers account for the oldest rocks because they haven been worn out due to erosion and others natural events. Thus, one can say that the more worn-out the rock is, the older it is when we want to analyze a new section of strata.
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Answer:
The correct answer:
8)- e)2, 2 dymetilpropane
9)- b) 2-chloropropane
10)- b) hydroxyl
See the explanation below, please.
Explanation:
In the cases of exercises 8 and 9:
Correspond to alkanes, having 3 carbons are named with the prefix prop and suffix anus. In 8 it has 2, 2 methyl groups in carbon and 9 in a 2-carbon chlorine group.
In the case of 10, it corresponds to a 3-carbon alcohol: suffix prop, and prefix ol: 2- propanol; in group 2 it has an OH group corresponding to alcohol (hydroxyl).
Answer:
15%
Explanation:
From the question given above, the following data were obtained:
Mass of sugar = 15 g
Mass of water = 85 g
Percentage of sugar in the solution =?
Next, we shall determine the mass of the solution. This can be obtained as follow:
Mass of solute (sugar) = 15 g
Mass of solvent (water) = 85 g
Mass of solution =?
Mass of solution = mass of solute + mass of solvent
Mass of solution = 15 + 85
Mass of solution = 100 g
Finally, we shall determine the percentage of the sugar in the solution. This can be obtained as follow:
Mass of solute (sugar) = 15 g
Mass of solution = 100 g
Percentage of sugar in the solution =?
Percentage = solute /solution × 100
Percentage = 15 / 100 × 100
Percentage of sugar in the solution = 15%
