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Ivanshal [37]
3 years ago
12

Approximately what percentage of the almost 1,500

Physics
1 answer:
victus00 [196]3 years ago
5 0

Answer:

50% are attributed to aggressive driving

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could you help me with this question: Aspherical shell is formed by taking a solid sphere of radius 24.0 cm and hollowing out a
kumpel [21]

Answer:

La vdd tengo la misma duda, de q prepa eres?

Explanation:

Nada más para saber

5 0
3 years ago
suppose an electrically charged ruler transfers some of its charge by contact to a tiny plastic sphere. will the ruler and the s
poizon [28]

Answer:

Here ball and rod will repel each other as they are of similar charges

Explanation:

As we know that the two charges attract or repel each other by electrostatic force

This force is given as

F = \frac{kq_1q_2}{r^2}

so we know if two charges are similar in nature then they will repel each other and if the two charges are opposite in nature then they will attract each other

So here when rod touch the ball then it transfer its charge to the ball and due to similar charges in ball and rod they both repel each other

5 0
3 years ago
The magnetic field or force seems to be associated with the lineup of____________ within the magnet.
Nastasia [14]
The magnetic field or force seems to be associated with the lineup of electrons withim the magnet
6 0
3 years ago
Read 2 more answers
A(n) _____ is a gap in the geologic record where some rock layers have been lost because of erosion.
Elenna [48]
I'm not sure, I think it's option A.

Let me know if I'm wrong!
4 0
3 years ago
After landing on an unfamiliar planet, a space explorer constructs a simple pendulum of length 53.0 cm . The explorer finds that
larisa86 [58]

Answer:

12.4 m/s²

Explanation:

L = length of the simple pendulum = 53 cm = 0.53 m

n = Number of full swing cycles = 99.0

t = Total time taken = 128 s

T = Time period of the pendulum

g = magnitude of gravitational acceleration on the planet

Time period of the pendulum is given as

T = \frac{t}{n}

T = \frac{128}{99}

T = 1.3 sec

Time period of the pendulum is also given as

T = 2\pi \sqrt{\frac{L}{g}}

1.3 = 2(3.14) \sqrt{\frac{0.53}{g}}

g = 12.4 m/s²

4 0
3 years ago
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