F=ma make m the subject
1 answer:
You might be interested in
Answer: F=0.075N
Explanation:
T*cos(θ) = mg=0.005X9.8
T*cos(θ)=0.049N
T = 0.049/cosθ
F = k*q1*q2 / r2
F = 8.9875 * 10^9 * q1*q2 / r^2 q1
F = 8.9875 * 10^9 * (5 x 10^-6)^2 / r^2
F=0.2246875/r^2
r= 2Lsinθ = 2 x 1 x sinθ =2sinθ
Kindly check the attached for further solution
Answer:
Explanation:
It is given that,
Mass of the baseball, m = 0.14 kg
It is dropped form a height of 1.8 m above the ground. Let u is the velocity when it hits the ground. Using the conservation of energy as :
h = 1.8 m
u = 5.93 m/s
Let v is the speed of the ball when it rebounds. Again using the conservation of energy to find it :
h' = 1.4 m
v = -5.23 m/s
The change in the momentum of the ball is given by :
So, the change in the ball's momentum occurs when the ball hits the ground is 1.56 kg-m/s. Hence, this is the required solution.