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Dmitry_Shevchenko [17]
3 years ago
8

The windmill has 7 blades and rotates at an angular speed of 0.5 rad/s. The opening between successive blades is equal to the wi

dth of a blade. A golf ball of diameter 9.0 x 10⁻² m is just passing by one of the rotating blades at a minimum speed of 0.1 m/s.
What is the angular acceleration of the windmill?
Physics
1 answer:
spin [16.1K]3 years ago
7 0

Answer:

α = - 0.00148 rad/s^2

Explanation:

Given:-

- The number of blades, n = 7

- The angular speed of blades, w = 0.5 rad/s

- The diameter of golf ball, d = 9.0 x 10^-2 m

- The speed of the ball, v = 0.1 m/s

Find:-

What is the angular acceleration of the windmill?

Solution:-

- We first need to visualize the ball "just passing" through between two successive blades. First we will determine the time taken (t) for the golf-ball to just pass the blades i.e it travelled a distance equal to its diameter (d) with given speed (v) to avoid the blades.

                                      d = v*t

                                      t = d / v

                                      t = 0.09 / 0.1

                                      t = 0.9 s

- It takes t = 0.9s for the golf-ball to just pass the windmill. The same amount of time is taken by the windmill blade to cover an arc distance (s) that is equivalent to the diameter of the ball (d) which is also the width of empty space between two successive blades. The angle (θ) between each blade - denoting empty space can be determined by the seeing that all 7 blades are equally spaced in a circle. So:

                                    θ = 2π / 2*n

                                    θ = π / 7

                                    θ = 0.44879 rads

- So the angular speed of the windmill blade (wf) when the ball passes through can be determined by the formula:

                                    wf = θ / t

                                    wf = 0.44879 / 0.9

                                    wf = 0.49866 rad/s

- Now we will use the first rotational kinematics equation of motion with constant angular acceleration ( α ) as follows:

                                   wf = wi + α*t

- Solve for  ( α ) :

                                    α = ( wf - wi ) / t

- Plug in the values and evaluate ( α ):

                                    α = ( 0.49866 - 0.5 ) / 0.9

                                    α = - 0.00148 rad/s^2

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<em></em>

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Technician A says that the freezing point of a substance is the temperature at which the substance changes state from a solid to
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Technician B is correct

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Based on the above explanation, it can be concluded that technician B is correct.

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3 years ago
The gas in a balloon has T=280 K and V=0.0279 m^3. if the temperature increases to 320 K at constant pressure, what is the new v
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Since P, n, and R are held constant:

n₁ R / P₁ = n₂ R₂ / P₂

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V₁ / T₁ = V₂ / T₂

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0.0279 m³ / 280 K = V / 320 K

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8 0
3 years ago
A 7.5-cmcm-diameter horizontal pipe gradually narrows to 4.5 cmcm . When water flows through this pipe at a certain rate, the ga
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Answer

given,

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flow in the pipe is equal to 6.38 x 10⁻³ m³/s

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