1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Dmitry_Shevchenko [17]
3 years ago
8

The windmill has 7 blades and rotates at an angular speed of 0.5 rad/s. The opening between successive blades is equal to the wi

dth of a blade. A golf ball of diameter 9.0 x 10⁻² m is just passing by one of the rotating blades at a minimum speed of 0.1 m/s.
What is the angular acceleration of the windmill?
Physics
1 answer:
spin [16.1K]3 years ago
7 0

Answer:

α = - 0.00148 rad/s^2

Explanation:

Given:-

- The number of blades, n = 7

- The angular speed of blades, w = 0.5 rad/s

- The diameter of golf ball, d = 9.0 x 10^-2 m

- The speed of the ball, v = 0.1 m/s

Find:-

What is the angular acceleration of the windmill?

Solution:-

- We first need to visualize the ball "just passing" through between two successive blades. First we will determine the time taken (t) for the golf-ball to just pass the blades i.e it travelled a distance equal to its diameter (d) with given speed (v) to avoid the blades.

                                      d = v*t

                                      t = d / v

                                      t = 0.09 / 0.1

                                      t = 0.9 s

- It takes t = 0.9s for the golf-ball to just pass the windmill. The same amount of time is taken by the windmill blade to cover an arc distance (s) that is equivalent to the diameter of the ball (d) which is also the width of empty space between two successive blades. The angle (θ) between each blade - denoting empty space can be determined by the seeing that all 7 blades are equally spaced in a circle. So:

                                    θ = 2π / 2*n

                                    θ = π / 7

                                    θ = 0.44879 rads

- So the angular speed of the windmill blade (wf) when the ball passes through can be determined by the formula:

                                    wf = θ / t

                                    wf = 0.44879 / 0.9

                                    wf = 0.49866 rad/s

- Now we will use the first rotational kinematics equation of motion with constant angular acceleration ( α ) as follows:

                                   wf = wi + α*t

- Solve for  ( α ) :

                                    α = ( wf - wi ) / t

- Plug in the values and evaluate ( α ):

                                    α = ( 0.49866 - 0.5 ) / 0.9

                                    α = - 0.00148 rad/s^2

You might be interested in
Which element is stable and nonreactive?
const2013 [10]
The answer is D. Krypton (kr)
6 0
4 years ago
The resistance of a wire depends on
Orlov [11]

Answer:

b

Explanation:

because all are factors that determine the resistivity of a material

6 0
3 years ago
Water flows straight down from an open faucet. The cross-sectional area of the faucet is 2.4 × 10-4m2 and the speed of the water
Ksenya-84 [330]

To solve this problem it is necessary to apply the continuity equations in the fluid and the kinematic equation for the description of the displacement, velocity and acceleration.

By definition the movement of the Fluid under the terms of Speed, acceleration and displacement is,

v_2^2 = v_1^2 + 2gh

Where,

V_i = Velocity in each state

g= Gravity

h = Height

Our values are given as,

A_1 = 2.4*10^{-4} m^2

v_1 = 0.8 m/s

h = 0.11m

Replacing at the kinetic equation to find V_2 we have,

v_2 = \sqrt{v_1^2 + 2gh}

v_2 = \sqrt{(0.8 m/s)^2 + 2(9.80 m/s2)(0.11 m)}

v_2= 1.67 m/s

Applying the concepts of continuity,

A_1v_1 = A_2v_2

We need to find A_2 then,

A_2= \frac{A_1v_1 }{v_2}

So the cross sectional area of the water stream at a point 0.11 m below the faucet is

A_2= \frac{A_1v_1 }{v_2}

A_2= \frac{(2.4*10^{-4})(0.8)}{(1.67)}

A_2= 1.14*10^{-4} m2

Therefore the cross-sectional area of the water stream at a point 0.11 m below the faucet is 1.14*10^{-4} m2

8 0
3 years ago
A man wishes to pull a crate 15m across a rough floor by exerting a force of 100 N. The
Darina [25.2K]

Answer:

option (E) is correct.

Explanation:

Work done is defined as the product of force and the distance in the direction of force.

force, f = 100 N

Coefficient of friction, = 0.25

distance = 15 m

So, net force F = f - friction force

F = 100 - 0.25 x m g

Work = (100 - 0.25 mg) x d cosθ

For minimum work, the angle should be maximum.

So, the value of θ is 76°.

thus, option (E) is correct.

3 0
3 years ago
A 1.00 kg object is attached to a horizontal spring. the spring is initially stretched by 0.500 m, and the object is released fr
valina [46]
The  spring is initially stretched, and the mass released from rest (v=0). The next time the speed becomes zero again is when the spring is fully compressed, and the mass is on the opposite side of the spring with respect to its equilibrium position, after a time t=0.100 s. This corresponds to half oscillation of the system. Therefore, the period of a full oscillation of the system is
T=2 t = 2 \cdot 0.100 s = 0.200 s
Which means that the frequency is
f= \frac{1}{T}= \frac{1}{0.200 s}=5 Hz
and the angular frequency is
\omega=2 \pi f = 2 \pi (5 Hz)=31.4 rad/s

In a spring-mass system, the maximum velocity of the object is given by
v_{max} = A \omega
where A is the amplitude of the oscillation. In our problem, the amplitude of the motion corresponds to the initial displacement of the object (A=0.500 m), therefore the maximum velocity is
v_{max} = A \omega = (0.500 m)(31.4 rad/s)= 15.7 m/s
6 0
4 years ago
Other questions:
  • A sound wave has a frequency of 615 hz in air and a wavelength of 0.54 m. what is the temperature of the air? assume the velocit
    5·1 answer
  • In which switching technique, a dedicated
    12·1 answer
  • In the following reaction, identify the missing particle:
    15·1 answer
  • Light of a single frequency falls on a photo-electric material but no electrons are emitted . Electrons may be emitted if the __
    11·1 answer
  • A sailboat starts from rest and accelerates at a rate of 0.21 m/s^2 over a distance of 280 m. find the magnitude of the boat's f
    6·1 answer
  • Release an electron initially at rest in the presence of an electric field. The electron tends to go to the region of 1. same el
    13·1 answer
  • HURRY IM TIMED!!!!Anya knows the velocity of an object. What else does she need to know in order to find the object’s momentum?
    8·2 answers
  • Which of the following is NOT a natural source of light?
    9·2 answers
  • When the moving sidewalk at the airport is broken, as it often seems to be, it takes you 41 ss to walk from your gate to baggage
    12·1 answer
  • 1. Why do certain elements have isotopes?
    7·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!