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andrew-mc [135]
1 year ago
14

If a 1500 V load is ac coupled to the output in Figure 9–60, what is the resulting output voltage (rms) when a 50 mV rms input i

s applied? gm = 5000 mS.
Engineering
1 answer:
Vilka [71]1 year ago
4 0

The resulting output voltage (rms) when a 50 mV rms input applied is  -187.5 mV.

<h3>What is rms voltage?</h3>

Root Mean Square Voltage is the amount of AC power which produces the same heating effect as DC Power would have produced.

Vo = -gm x Vi (Rd II Rl )

Vo = -5000 x  10⁻⁶ x 50 x 10⁻³ x (1.5k II 1.5k )

Vo = -25 x 10⁻² x 750 x  10⁻³

Vo = -187.5 mV

Hence, resulting output voltage (rms) when a 50 mV rms input applied is   -187.5 mV.

Learn more about rms voltage.

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Consider an aircraft powered by a turbojet engine that has a pressure ratio of 9. The aircraft is stationary on the ground, held
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The break force that must be applied to hold the plane stationary is 12597.4 N

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\dfrac{T_{2}}{T_{1}} = \left (\dfrac{P_{2}}{P_{1}}  \right )^{\frac{K-1}{k} }

{T_{2}}{} = T_{1} \times \left (\dfrac{P_{2}}{P_{1}}  \right )^{\frac{K-1}{k} } = 280.15 \times \left (9  \right )^{\frac{1.333-1}{1.333} } = 485.03\ K

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The heat supplied = 0.5 kg/s × 42,700 kJ/kg = 21,350 kJ/s

The heat supplied = \dot m · c_p(T_3 - T_2)

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The heat supplied = 20*c_p(T_3 - T_2) = 21,350 kJ/s

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p₃ = p₂ = 855 kPa

T₃ - T₄ = T₂ - T₁ = 485.03 - 280.15 = 204.88 K

T₄ = 1413.3 - 204.88 = 1208.42 K

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T₅ = 1208.42*(2/2.333) = 1035.94 K

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The total thrust = \dot m × C_j = 20*629.87 = 12597.4 N

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The break force that must be applied to hold the plane stationary = 12597.4 N.

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