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viktelen [127]
3 years ago
5

A car engine operates with a thermal efficiency of 20%. Assume the air-conditioner has a coefficient of performance of β = 2 wor

king as a refrigerator cooling the passenger compartment using engine shaft work to drive it. How much fuel energy per second is spent extra to remove 8 kJ/sec from the inside?
Engineering
1 answer:
disa [49]3 years ago
5 0

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You and your design group are competing for a multidisciplinary concept project. Your firm is the lead group in the design profe
sasho [114]

Answer: the answer for the question is a

Explanation:

4 0
3 years ago
The Reynolds number for flow over a fixed horizontal flat plate is constant throughout its length. a) True b) False
ANTONII [103]

Answer: False

Explanation: Reynolds number is the number for determining he flow pattern of the behavior of fluids.It judges the flow of the fluid ans states whether it is of turbulent or laminar natured. This number has the property of kinematics as well as statics. It can also be defined as the ratio between the inertial force to viscous force.It's length changes along with change length of the horizontal plate .Thus, the statement given is false.

5 0
4 years ago
1. A cylindrical casting is 0.3 m in diameter and 0.5 m in length. Another casting has the same metal is rectangular in cross-se
Lorico [155]

Based on the Chvorinov's rule, the diference in the <em>solidification</em> times of the two castings is 14.092 times the <em>solidification</em> time of the prism casting.

<h3>How to apply the Chvorinov's rule for casting processes</h3>

The Chvorinov's rule is an empirical method to estimate the cooling time of a casting in terms of a <em>reference</em> time. This rule states that cooling time (<em>t</em>) is directly proportional to the square of the volume (<em>V</em>), in cubic meters, divided to the surface area (<em>A</em>), in square meters. Now we proceed to model each casting:

<h3>Cylindrical casting</h3>

t = C · [0.25π · D² · L/(0.5π · D² + π · D · L)]²

t = C · [0.25 · D · L/(0.5 · D + L)]²    (1)

<h3>Prism casting</h3>

t' = C · [3 · T² · L/(6 · T · L + 2 · T · L + 6 · T²)]²

t' = C · [3 · T · L/(8 · L + 6 · T)]²     (2)

<h3>Relationship between the cross sections of both castings</h3>

3 · T² = 0.25π · D²     (3)

Where:

  • <em>t</em> - Cooling time of the cylindrical casting, in time unit.
  • <em>t'</em> - Cooling time of the prism casting, in time unit.
  • <em>C</em> - Cooling factor, in time unit per square meter.
  • <em>D</em> - Diameter of the cylinder, in meters.
  • <em>L</em> - Length of the casting, in meters.
  • <em>T</em> - Width of the cross section of the prism casting, in meters.

If we know that <em>D =</em> <em>0.3 m</em>, then the thickness of the prism casting is:

T = \sqrt{\frac{\pi}{12} }\cdot D

<em>T ≈ 0.153 m</em>

<em />

And (1) and (2) simplified into these forms:

<h3>Cylindrical casting</h3>

t = C · {0.25π · (0.3 m) · (0.5 m)/[0.5 · (0.3 m) + 0.5 m]}²

t = 0.0329 · C     (1b)

<h3>Prism casting</h3>

t' = C · {3 · (0.153 m) · (0.5 m)/[8 · (0.5 m) + 6 · (0.153 m)]}²

t' = 0.00218 · C     (2b)

Lastly we find the <em>percentual</em> difference in the solidification times of the two castings by using the following expression:

<em>r = (</em>1 <em>- t'/t) ×</em> 100 %

<em>r = (</em>1 <em>-</em> 0.00218<em>/</em>0.0329<em>) ×</em> 100 %

<em>r =</em> 93.374 %

The <em>cooling</em> time of the <em>prism</em> casting is 6.626 % of the <em>solidification</em> time of the <em>cylindrical</em> casting. The diference in the <em>solidification</em> times of the two castings is 14.092 times the <em>solidification</em> time of the <em>prism</em> casting. \blacksquare

To learn more on solidification times, we kindly invite to check this verified question: brainly.com/question/13536247

3 0
3 years ago
I NEED HELP NOW!!!!!!!!!!!!!!
Greeley [361]

Answer:

S or the 4th option

Explanation:

THIS IS SO EASY

8 0
3 years ago
Read 2 more answers
A positively charged electric has a charge of 2 Coulombs. If 12.5x10^18 free electrons are added to it, what will be the net cha
vitfil [10]

The net charge on the said dielectric is 0

1C = 6.25 * 10¹⁸ electrons; hence:

-12.5x10¹⁸ free electrons = (-12.5x10¹⁸ free electrons * (1C/ 6.25 * 10¹⁸ electrons))

-12.5x10¹⁸ free electrons = -2 C

A positively charged electric has a charge of 2 Coulombs, hence:

Q₁ = 2C

12.5x10¹⁸ free electrons are added to it, hence:

Q₂ = -2C

Net\ charge(Q_{net})=Q_1+Q_2=2C+(-2C)=0

Hence the net charge on the said dielectric is 0

Find out more at: brainly.com/question/10464929

3 0
3 years ago
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