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KiRa [710]
3 years ago
15

A charged particle moves through a velocity selector at a constant speed in a straight line. The electric field of the velocity

selector is 3.50 × 10 3 N/C, while the magnetic field is 0.270 T. When the electric field is turned off, the charged particle travels on a circular path whose radius is 4.70 cm. Find the charge-to-mass ratio of the particle.
Physics
1 answer:
vlada-n [284]3 years ago
5 0

47.0989846 is the answer i got

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Answer:

The distance the piece travel in horizontally axis is

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Explanation:

a=2 \frac{rev}{s^{2}} \\h=0.820m\\r = 0.125 m&#10;\\d=150rev

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d=d_{i}+vo*t+\frac{1}{2}*a*t^{2} \\ di=0\\vo=0\\d=\frac{1}{2}*a*t^{2}\\t=\sqrt{\frac{2*d}{a}}\\t=\sqrt{\frac{2*310 rad}{4\frac{rad}{s^{2}}}} \\t=12.449

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t=\sqrt{\frac{2*h}{g}}\\t=\sqrt{\frac{2*0.820m}{9.8\frac{m}{s^{2} } }}\\t=0.409s

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L=t*V\\L=0.409s*8.7\frac{m}{s}\\L=3.55m

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