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Fed [463]
3 years ago
10

What happens when a roller coaster car moves down from the top of a hill?

Physics
2 answers:
VARVARA [1.3K]3 years ago
6 0

-- It accelerates.
-- Its speed increases.
-- It gains momentum.
-- It loses altitude.
-- It loses potential energy.
-- It gains kinetic energy.
-- Its wheels make a lot of noise.
-- Everybody screams.

Stella [2.4K]3 years ago
3 0

Potential energy is transformed into kinetic and thermal energy.


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Use the information from the graph to answer the question.
galina1969 [7]

The displacement of the object as determined from the velocity-time graph is 562.5 m.

<h3>What is a velocity-time graph?</h3>

A velocity-time graph is a graph of the velocity of an object plotted in the vertical or y-axis of the graph against the time taken on the horizontal or x-axis.

The displacement of an object can be obtained from its velocity-time graph by calculating the total area under the graph.

The total area under the graph = area of triangle + area of rectangle

Area of triangle = b*h/2 =

Area of triangle = 25 * (35 - 10)/2 = 312.5 m

Area of rectangle = l * b

Area of rectangle = 10 * 25 = 250 m

Total area = (312.5 + 250) m

Total area = 562.5 m

Therefore, the displacement of the object is 562.5 m

In conclusion, the total area of a velocity-time graph gives the displacement.

Learn more about velocity-time graph at: brainly.com/question/28064297

#SPJ1

5 0
1 year ago
There are two possibilities for final stage of extremely massive stars. The first is a
makkiz [27]

Answer: Black hole.

Explanation:

As the massive star "compacts" under its own gravity, it triggers a massive supernova, after this point the remains of the star can become a neutron star, which is a very compact star made primarily, as the name says, of neutrons. The other possibility is a black hole, which is a finite region of space wherein it's interior there is a big concentration of mass, which creates a gravitational field strong enough that there is no particle that can escape it.

3 0
3 years ago
Why can’t you hit a feather in mid air with a force of 200 N<br> (This is all the info I was given)
Aloiza [94]
You cannot for real ehhhh
5 0
2 years ago
A boy whirls a stone in a horizontal circle of radius 1.50m and at height 2.00m above level ground. The string breaks, and the s
Eddi Din [679]

Answer:

a_{cp}=162.2m/s^2

Explanation:

The time the stone takes to fall can be calculated considering only the vertical component with the formula:

y=y_0+v_{0y}t+\frac{a_yt^2}{2}

Taking the inital height as 0m and downward direction positive, since it departs from (vertical) rest we have:

y=\frac{gt^2}{2}

Which gives us a time:

t=\sqrt{\frac{2y}{g}}=\sqrt{\frac{2(2m)}{(9.8m/s^2)}}=0.64s

Horizontally, on that time the stone travelled a distance x=10m, which means its horizontal speed was:

v_x=\frac{x}{t}=\frac{10m}{0.64s}=15.6m/s

Since <u>this speed is the tangential velocity</u> while whirling, the centripetal acceleration of the stone was:

a_{cp}=\frac{v_x^2}{r}=\frac{(15.6m/s)^2}{(1.5m)}=162.2m/s^2

7 0
3 years ago
Calculate the electric charge of the glass ball
-Dominant- [34]

Answer:

As per Coulomb's law we know that force between two charges is given as

F = \frac{kq_1q_2}{r^2}F=

r

2

kq

1

q

2

here we know that

q_1 = 2.5 \times 10^{-6} Cq

1

=2.5×10

−6

C

q_2 = -5.0 \times 10^{-6} Cq

2

=−5.0×10

−6

C

r = 0.0050 mr=0.0050m

now from above formula we will have

F = \frac{(9 \times 10^9)(2.5 \times 10^{-6})(5 \times 10^{-6})}{(0.0050)^2}F=

(0.0050)

2

(9×10

9

)(2.5×10

−6

)(5×10

−6

)

F = 4500 NF=4500N

so they will attract towards each other as they are opposite in nature with force F = 4500 N

4 0
2 years ago
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