Which body is in equilibrium?
(1) a satellite orbiting Earth in a circular orbit
. No. The forces on it are unbalanced. There's only one force acting on it ... the force of gravity, pulling it toward the center of the Earth. That's a centripetal force, and the satellite is experiencing centripetal acceleration.
(2) a ball falling freely toward the surface of Earth. No. The forces on it are unbalanced. There's only one force acting on it ... the force of gravity, pulling it toward the center of the Earth. The ball is accelerating toward the ground.
<em>
(3) a car moving with a constant speed along a straight, level road. YES.</em> We don't even need to analyze the forces, just look at the car. It's moving in a straight line, and its speed is not changing. The car's acceleration is zero ! That right there tells us that the NET force ... the sum of all forces acting on the car ... is zero. THAT's called 'equilibrium'.
(4) a projectile at the highest point in its trajectory. No. The forces on it are unbalanced. There's only one force acting on it ... the force of gravity, pulling it toward the center of the Earth. The projectile is accelerating toward the ground.
Answer:
C 3.6 cm, 56 degrees North of the East axis
Explanation:
The two vectors are perpendicular to each other, so we can find the magnitude of their resultant simply by using the Pythagorean theorem:
![R=\sqrt{A^2+B^2}](https://tex.z-dn.net/?f=R%3D%5Csqrt%7BA%5E2%2BB%5E2%7D)
where
A = 2.0 cm is the magnitude of the first vector
B = 3.0 cm is the magnitude of the second vector
Substituting,
![R=\sqrt{2^2+3^2}=3.6 cm](https://tex.z-dn.net/?f=R%3D%5Csqrt%7B2%5E2%2B3%5E2%7D%3D3.6%20cm)
Now we have to find the angle. If we measure the angle as North of East, the tangent of the angle is equal to the ratio between the component along North and the component along East. Therefore, in this case:
![tan \theta = \frac{B}{A}=\frac{3}{2}=1.5\\\theta = tan^{-1}(1.5)=56.3 \sim 56^{\circ}](https://tex.z-dn.net/?f=tan%20%5Ctheta%20%3D%20%5Cfrac%7BB%7D%7BA%7D%3D%5Cfrac%7B3%7D%7B2%7D%3D1.5%5C%5C%5Ctheta%20%3D%20tan%5E%7B-1%7D%281.5%29%3D56.3%20%5Csim%2056%5E%7B%5Ccirc%7D)
So, 56 degrees North of East.
This distance is called the wave length, from crest to crest or trough to trough.
for this we apply, Heisenberg's uncertainty principle.
it states that physical variables like position and momentum, can never simultaneously know both variables at the same moment.
the formula is,
Δp * Δx = h/4π
m(e).Δv * Δx = h/4π
by rearranging,
Δx = h / 4π * m(e).Δv
Δx = (6.63*10^-34) / 4 * 3.142 * 9.11*10^-31 * 5.10*10^-2
Δx = 6.63*10^-34 / 583.9 X 10 ⁻³¹
Δx = 0.011 X 10⁻³
for the bullet
Δx = (6.63*10^-34) / 4 * 3.142 * 0.032*10^-31 * 5.10*10^-2
Δx = 6.63*10^-34 /2.05
Δx =3.23 X 10⁻³² m
therefore, we can say that the lower limits are 0.011 X 10⁻³ m for the electron and 3.23 X 10⁻³² m for the bullet
To know more about bullet problem,
brainly.com/question/21150302
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