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Bas_tet [7]
2 years ago
6

If 4.89 g of ZnCl2 is dissolved in enough water to give a total volume of 500 mL, what is the molarity of the solution

Chemistry
1 answer:
Molodets [167]2 years ago
5 0

Answer:

Molarity = 0.08 M

Explanation:

Given data:

Mass of ZnCl₂ = 4.89 g

Volume of water = 500 mL (500 mL× 1L/1000 mL= 0.5 L)

Molarity of solution = ?

Solution:

Molarity is used to describe the concentration of solution. It tells how many moles are dissolve in per litter of solution.

Formula:

Molarity = number of moles of solute / L of solution

Number of mole ZnCl₂:

Number of moles = mass/molar mass

Number of moles = 4.89 g/ 136.3 g/mol

Number of moles = 0.04 mol

Molarity:

M = 0.04 mol / 0.5 L

M = 0.08 M

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If 10 g of NaOH is diluted to 500 ml with water then  the concentration expressed in percent is 0.5 mol/L .

Calculation ,

Given mass in gram = 10 g

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Given volume in ml = 500 ml

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Putting the value of mass and volume in equation i we get concentration expressed in percent .

C = number of moles ×100/ volume in liter = 0.25mole ×100/ 0.5 L

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Concentration of solution in terms of percentage can be expressed in two ways

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Hence, for liquid solutions, concentration is expressed in terms of percentage by volume.  

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