Answer:
Volume of balloon will be doubled
Explanation:
We are asked to state what happens to a balloon which was placed in a closed chamber at STP if the temperature is doubled and the pressure is kept constant.
We have three parameters here, the temperature and pressure of the chamber, and the volume of the balloon.
Now, since the pressure of the chamber is kept constant, we can say that the gas law we need to use is the Charles’ law and it posits that volume and temperature are directly proportional:
Given;
V1 =? , V2 = ?, T1 = 273.15K(at STP) and T2 = 273.15 * 2 = 546.3K
We substitute these values in the Charles’ law equation:
V1/T1 = V2/T2
V2 = V1T2/T1
V2 = (V1 * 546.3)/273.15
V2 = 2V1
This means that the balloon will double in volume
