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il63 [147K]
3 years ago
11

4x + 16 - x= 22 + 6 O A. x = 3 O B. x= 2 O C. x = 4 D. x = 11

Mathematics
2 answers:
stiks02 [169]3 years ago
7 0

Answer:

The Answer is C

Step-by-step explanation:

22+6= 28

4(4)+16-4=28

Thus, the answer is C, X=4.

Alex_Xolod [135]3 years ago
7 0

Answer:

C. x=4

Step-by-step explanation:

4x-x=22+6-16

3x=12

x=12÷3

x=4

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A green cross is formed by placing two rectangles of dimensions 8cm×4cm over
Goshia [24]

Answer:

<em>The perimeter of the green cross is 32 cm</em>

Step-by-step explanation:

<u>Perimeter</u>

It's the sum of all the external side lengths of a given shape.

The green cross formed by two rectangles is shown in the figure below.

We have outlined the dimensions of the external sides of the resulting cross.

Note there are four corners of 2 cm by 2 cm and four sides of 4 cm each.

The total perimeter is:

8 * 2 cm + 4 * 4 cm = 16 cm + 16 cm = 32 cm

The perimeter of the green cross is 32 cm

4 0
2 years ago
If the growth rate of bacteria at any time t is proportional to the number present at t and triples in 1 week
serg [7]

The population after 20 weeks will be 403.42x_{0} in which x_{0} is the initial population.

Given that the growth rate of bacteria at any time t is proportional to the number present at t and triples in 1 week.

We are required to find the number of bacteria present after 10 weeks.

let the number of bacteria present at t is x.

So,

dx/dt∝x

dx/dt=kx

1/x dx=k dt

Now integrate both sides.

\int\limits {1/x} \, dx=\int\limits{k} \, dt

log x=kt+log c----------1

Put t=0

log x_{0}=0 +log c    (x_{0} shows the population in beginning)

Cancelling log from both sides.

c=x_{0}

So put c=x_{0} in 1

log x=kt+log x_{0}

log x=log e^{kt}+log x_{0}

log x=log e^{kt}x_{0}

x=e^{kt}x_{0}

We have been given that the population triples in a week so we have to put the value of x=2x_{0} and t=1 to get the value of k.

2x_{0}=e^{k} x_{0}

2=e^{k}

log 2=k

We have to now put the value of t=20 and k=log 2 ,to get the population after 20 weeks.

x=e^{20log 2}x_{0}

x=e^{0.30*2}x_{0}

x=e^{6}x_{0}

x=403.42x_{0}

Hence the population after 20 weeks will be 403.42x_{0} in which x_{0} is the initial population.

Learn more about growth rate at brainly.com/question/25849702

#SPJ4

The given question is incomplete as the question incudes the following:

Calculate the population after 20 weeks.

5 0
2 years ago
How many kilometers are in 2 meters and in 13 meters
aivan3 [116]

there  Are 2000 Kilometers in 2 meter

There Are 13000 Kilometers in 13 meters


7 0
2 years ago
Need help with a math question PLEASE HELP
navik [9.2K]

Answer:

(-1, -3)

Step-by-step explanation:

We suppose your notation means you want to reflect given point P across the horizontal line y=1.

The x-coordinate will remain the same.

The new y-coordinate will be such that y=1 is the midpoint between the original and its reflection:

(5 + y)/2 = 1

5 + y = 2 . . . . multiply by 2

y = 2 -5 = -3 . . . subtract 5

The reflected point is (-1, -3).

___

The same sort of math applies whenever you have a midpoint and want to find the other end point. Double the midpoint value and subtract the end point you have in order to find the other end point.

4 0
3 years ago
Can someone help please ?
Murljashka [212]

Answer:

-22

Step-by-step explanation:

equantion: (n + 15).6= -42

n = -22

7 0
3 years ago
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