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4 years ago

What did Rutherford’s scattering experiment reveal about the structure of atoms?

Chemistry

1 answer:

Stels [109]4 years ago

7 0

Answer:

Explanation:

This experiment by Rutherford involved the firing of alpha particles at gold foils. It is also. called the gold foil experiment.

He fired these alpha particles at different points. He noticed that at some points, there were deflections, while at some other points, there were no deflections. It is necessary to state that these alpha particles are positively charged. For there to be a deflection, there must have been a kind of repulsion between the gold foil and the alpha particles.

From the basic physics of like repels like, he knew for sure that there must be dense positive core in the atom that is causing the deflection of the alpha particles. This enabled him to come up with the theory that the atom contained a small dense positive core called the nucleus

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Can you help me please

Iteru [2.4K]

Alright, so a few seem almost self-explanatory.
"Energy from moving air" -> wind
"Energy in waves from the sun" -> solar.
But I digress.
The list goes (in order of the descriptions):
9 (Black rock...)
7 (Heat inside the Earth...)
8 (Flowing water...)
3 (Wood, waste, and garbage...)
2 (Moving air...)
4 (Splitting atoms...)
5 (Portable fossil fuel...)
1 (Used by cars...) petroleum is gasoline when refined
10 (Moved by pipeline...) This is true of petroleum too, but we don't burn natural gas in cars.
6 (Waves from the sun...)

7 0

3 years ago

Read 2 more answers

What is a wave produced by vibrating electric charges that can travel in matter and empty space?

Harman [31]

The answer is A

Explanation:

8 0

4 years ago

Read 2 more answers

You find a little bit (0.150g) of a chemical marked Tri-Nitro-Toluene. Upon complete combustion in oxygen, you collect 0.204 g o

Elan Coil [88]

Answer:

The empirical formula is C7H5N3O6

Explanation:

Step 1: Data given

Mass of sample = 0.150 grams

Mass of CO2 = 0.204 grams

Molar mass CO2 = 44.01 g/mol

Mass of H2O = 0.030 grams

Molar mass H2O = 18.02 g/mol

Molar mass C = 12.01 g/mol

Molar mass H = 1.01 g/mol

Molar mass O = 16.0 g/mol

Step 2: Calculate moles CO2

Moles CO2 = mass CO2 / molar mass CO2

Moles CO2 = 0.204 grams / 44.01 g/mol

Moles CO2 = 0.00464 moles

Step 3: Calculate moles C

For 1 mol CO2 we have 1 mol C

For 0.00464 moles we have 0.00464 moles C

Step 4: Calculate mass C

Mass C = 0.00464 moles * 12.01 g/mol

Mass C = 0.0557 grams

Step 5: Calculate moles H2O

Moles H2O = 0.030 grams / 18.02 g/mol

Moles H2O = 0.00166 moles

Step 6: Calculate moles H

For 1 mol H2O we have 2 moles H

For 0.00166 moles H2O we have 2* 0.00166 = 0.00332 moles H

Step 7: Calculate mass H

Mass H = 0.00332 moles * 1.01 g/mol

Mass H = 0.00335 grams

Step 8: Calculate mass N

Mass N = 0.185 * 0.150 grams

Mass N = 0.02775 grams

Step 9: Calculate moles N

Moles N = 0.02775 grams / 14.0 g/mol

Moles N = 0.00198 moles

Step 10: Calculate mass O

Mass O = 0.150 grams - 0.02775 - 0.00335 - 0.0557

Mass O = 0.0632 grams

Step 11: Calculate moles O

Moles O = 0.0632 grams / 16.0 g/mol

Moles O = 0.00395 moles

Step 11: Calculate mol ratio

We divide by the smallest amount of moles

C: 0.00464 moles / 0.00198 moles =2.33

H: 0.00332 moles / 0.00198 moles = 1.66

N: 0.00198 moles / 0.00198 moles = 1

O: 0.00395 moles / 0.00198 moles = 2

For 1 mol N we have 2.33 moles C, 1.66 moles H and 2 moles O

For 3 moles N we have 7 moles C, 5 moles H and 6 moles O

The empirical formula is C7H5N3O6

5 0

3 years ago

3) In 5 electron group molecules, what is the difference between axial and equatorial positions? Which groups are removed as lon

shusha [124]

The axial positions the bond angle is 120 degrees and in equatorial positions the bond angle is 90 degrees.

Functional groups on central atom gets reduce if lone pairs are added.

Explanation:

The number of lone pairs and base pairs of electrons tells the geometry of the molecule.

VSEPR Theory helps to know the lone pairs and bond pair electrons on the centre atom of the molecule.

Example of molecule containing 5 electron pairs can have four bond pairs and 1 lone pair.

eg: Cl $F_{3}$

the repulsion is shown as

lp-lp> lp-bp>bp-bp

These are in equatorial position because of the repulsion of lone pairs.

It can have 2 lone pairs and 3 bond pairs. eg. Xe $F_{2}$

Lone pairs in this is also in equatorial position as

lp-lp> lp-bp> bp-bp

In axial positions the bond angle is 120 degrees

in equatorial positions the bond angle is 90 degrees, due to the repulsion in lone pair of electrons.

If 1 lone pair is there it can be replaced by bonding with hydrogen.

If 2 lone pairs are there then bonding with oxygen is there. The covalent bond is formed.

7 0

3 years ago

In which grouping of the periodic table do the elements have similar properties?

Valentin [98]

Answer:

only columns

Explanation:

All atoms of elements present in same group or column having same number of valance electrons. Thus the elements in same group having same properties.

For example:

Consider the second group. It consist of alkaline earth metals. There are six elements in second group. Beryllium, magnesium, calcium, strontium, barium and radium.

All have two valance electrons.

Electronic configuration of Beryllium:

Be = [He] 2s²

Electronic configuration of magnesium.

Mg = [Ne] 3s²

Electronic configuration of calcium.

Ca = [Ar] 4s²

Electronic configuration of strontium.

Sr = [Kr] 5s²

Electronic configuration of barium.

Ba = [Xe] 6s²

Electronic configuration of radium.

Ra = [ Rn] 7s²

They are present in group two and have same number of valance electrons (two valance electrons) and show similar reactivity.

They react with oxygen and form oxide.

2Ba + O₂ → 2BaO

2Mg + O₂ → 2MgO

2Ca + O₂ → 2CaO

this oxide form hydroxide when react with water,

BaO + H₂O → Ba(OH)₂

MgO + H₂O → Mg(OH)₂

CaO + H₂O → Ca(OH)₂

With sulfur,

Mg + S → MgS

Ca + S → CaS

Ba + S → BaS

5 0

4 years ago