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3 years ago

What is the frequency of the light with a wavelength of 4.90x10^-7 m

Chemistry

1 answer:

docker41 [41]3 years ago

6 0

Answer: $6.12\times 10^{14}$ Hz

Explanation: Recall the formula for the speed of light is

$c=\lambda v$

where $c$ is the speed of light, $\lambda$ is the wavelength, and $v$ is the frequency. Assuming this takes place in a vacuum, $c=3.00\times 10^8$ m/s. Now we can solve for frequency

$c=\lambda v$

$3.00\times 10^8 = 4.90\times 10^{-7}\cdot v$

$v = \frac{3.00\times 10^8}{4.90\times 10^{-7}}$

$v =6.12\times 10^{14}$ (rounding to 3 sig figs)

Thus, the frequencyis $6.12\times 10^{14}$ Hz.

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What is the density of 53.4 wt aqueous naoh?

zhenek [66]

Missing question: what is the density of 53.4 wt% aqueous NaOH if 16.7 mL of the solution diluted to 2.00L gives 0.169 M NaOH?

Answer is: density is 1.52 g/mL.

c₁(NaOH) = ?; molarity of concentrated sodium hydroxide.

V₁(NaOH) = 16.7 mL; volume of concentrated sodium hydroxide.

c₂(NaOH) = 0.169 M; molarity of diluted sodium hydroxide.

V₂(NaOH) = 2.00 L · 1000 mL/L = 2000 mL; volume of diluted sodium hydroxide.

Use equation: c₁V₁ = c₂V₂.

c₁ = c₂V₂ / V₁.

c₁ = 0.169 M · 2000 mL / 16.7 mL.

c₁(NaOH) = 20.23 M.

m(NaOH) = 20.23 mol · 40 g/ml.

m(NaOH) = 809.53 g.

The mass fraction is the ratio of one substance (in this example sodium hydroxide) with mass to the mass of the total mixture (solution).

Make proportion: m(NaOH) : m(solution) = 53.4 g : 100 g.

m(solution) = 1516 g in one liter of solution.

d(solution) = 1516 g/L = 1.52 g/mL.

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3 years ago

Which of the following belong to a category called the main group of elements

Anna71 [15]

Answer:

C. Alkaline Metal ok thanks

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3 years ago

Read 2 more answers

Compare the ability to hold on to / attract electrons between metals and nonmetals.

skad [1K]

Nonmetals have the ability to attract electrons better than metals because they have a higher electron affinity or electronegativity than metals.

<h3>What is electronegativity?</h3>

Electronegativity is the tendency, or a measure of the ability, of an atom or molecule to attract electrons and thus form bonds.

An element in the periodic table with a high electronegativity will automatically have a high electron affinity.

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Learn more about electronegativity at: brainly.com/question/2060520

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2 years ago

Explain how chemicals and chemical reactions are an important part of our lives.

Zielflug [23.3K]

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3 years ago

2. Answer the following questions about a sample of calcium phosphate:

weqwewe [10]

Answer:

a) 310.18 g/mol

b) 4.352 moles Ca3(PO4)2

c) 2.6 * 10^24 molecules

d) 5.24 * 10^24 P atoms

e)13.056 moles Ca

f)10825.3 grams

Explanation:

Step 1: Data given

Atomic mass of Ca = 40.08 g/mol

Atomic mass of P = 30.97 g/mol

Atomic mass of O = 16.0 g/mol

Step 2: Calculate molecular weight of Ca3(PO4)2

Molecular weight of Ca3(PO4)2 = 3*atomic mass of Ca + 2* atomic mass of P and 8* atomic mass of O

Molecular weight of Ca3(PO4)2 = 3*40.08 + 2*30.97 + 8*16.0 = 310.18 g/mol

Step 3: Calculate moles of Ca3(PO4)2 in 1350 grams

Moles Ca3(PO4)2 = mass Ca3(PO4)2 /molar mass

Moles Ca3(PO4)2 = 1350 grams / 310.18 g/mol

Moles Ca3(PO4)2 = 4.352 moles

Step 4: Calculate molecules in 1350 grams

Molecules = moles * number of Avogadro

Molecules = 4.352 moles * 6.02 * 10^23

Molecules = 2.6 *10^24 molecules

Step 5: Calculate moles Phosphorus

For 1 mol Ca3(PO4)2 we need 2 moles P

For 4.352 moles Ca3(PO4)2 we have 2*4.352 = 8.704 moles

Step 6: Calculate P atoms

Atoms P = 8.704 moles * 6.02*10^23

Atoms P = 5.24 * 10^24 P atoms

Step 7: Calculate moles Calcium in 1350 grams

For 1 mol Ca3(PO4)2 we have 3 moles Ca

For 4.352 moles we have 3*4.352 = 13.056 moles Ca

Step 8: Calculate mass of 2.1 * 10^25 molecules of Ca3(PO4)2

Moles Ca3(PO4)2 = 2.1 * 10^25 / 6.02 * 10^23

Moles Ca3(PO4)2 = 34.9 moles

Mass Ca3(PO4)2 = 34.9 moles * 310.18 g/mol

Mass Ca3(PO4)2 = 10825.3 grams

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3 years ago