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Natalka [10]
3 years ago
15

what are simplified definitions of the following words"Synthesis, Decomposition, Single Replacement, or Double Replacement"?

Chemistry
1 answer:
faust18 [17]3 years ago
8 0

Answer:

The Four Major Types of Reactions

Name General Reaction Pattern

Combination or synthesis A + B ----> AB

Decomposition AB ----> A + B

Substitution or Single Replacement A + BC ----> B + AC

Metathesis or Double Displacement AB + CD ----> AD + CB

Combination or Synthesis Reactions Two or more reactants unite to form a single product.

S + O2 ---------> SO2

sulphur oxygen sulphur dioxide

2 S + 3 O2 ---------> 2 SO3

sulphur oxygen sulphur trioxide

2 Fe + O2 ---------> 2 FeO

iron oxygen iron (II) oxide

Decomposition Reactions A single reactant is decomposed or broken down into two or more

products.

CaCO3 ----------> CaO + CO2

calcium carbonate calcium oxide carbon dioxide

2 H2O -----------> 2 H2 + O2

water hydrogen oxygen

2 KClO3 -----------> 2 KCl + 3 O2

potassium chlorate potassium chloride oxygen

Substitution or Single Replacement Reactions A single free element replaces or is substituted for one of the elements in a compound. The free element is more reactive than the one its replaces.

Zn + 2 HCl ----------> H2 + ZnCl2

zinc hydrochloric acid hydrogen zinc chloride

Cu + 2 AgNO3 -----------> 2 Ag + Cu(NO3)2

copper silver nitrate silver copper (II) nitrate

H2 + 2 AgNO3 -----------> 2 Ag + 2 HNO3

hydrogen silver nitrate silver nitric acid

2 Na + 2 H2O -----------> 2 NaOH + H2

sodium water sodium hydroxide hydrogen

Metathesis or Double Displacement Reactions This reaction type can be viewed as an "exchange of partners." For ionic compounds, the positive ion in the first compound combines with the negative ion in the second compound, and the positive ion in the second compound combines with the negative ion in the first compound.

HCl + NaOH -----------> NaCl + HOH

hydrochloric sodium sodium water

acid hydroxide chloride

BaCl2 + 2 AgNO3 ----------> 2 AgCl + Ba(NO3)2

barium silver silver barium

chloride nitrate chloride nitrate

(precipitate)

CaCO3 + 2 HCl -----------> CaCl2 + H2CO3

calcium hydrochloric calcium carbonic

carbonate acid chloride acid

Explanation:

The vast number of chemical reactions can be classified in any number of ways. Under one scheme they can be categorized either as oxidation-reduction (electron transfer) reactions or non-oxidation-reduction reactions. Another completely different but common classification scheme recognizes

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Find the density of a piece of glass with a mass of 500g and a volume of 200cm3
kykrilka [37]
Density = mass/volume
D = 500 g /200 cm^3
D = 2.5 g/cm^3

hope this helps!
3 0
3 years ago
The vapor pressure of ethanol is 1.00 × 102 mmHg at 34.90°C. What is its vapor pressure at 60.21°C? (ΔHvap for ethanol is 39.3 k
Delicious77 [7]

Answer:

The vapor pressure at 60.21°C is 327 mmHg.

Explanation:

Given the vapor pressure of ethanol at 34.90°C is 102 mmHg.

We need to find vapor pressure at 60.21°C.

The Clausius-Clapeyron equation is often used to find the vapor pressure of pure liquid.

ln(\frac{P_2}{P_1})=\frac{\Delta_{vap}H}{R}(\frac{1}{T_1}-\frac{1}{T_2})

We have given in the question

P_1=102\ mmHg

T_1=34.90\°\ C=34.90+273.15=308.05\ K\\T_2=60.21\°\ C=60.21+273.15=333.36\ K\\\Delta{vap}H=39.3 kJ/mol

And R is the Universal Gas Constant.

R=0.008 314 kJ/Kmol

ln(\frac{P_2}{102})=\frac{39.3}{0.008314}(\frac{1}{308.05}-\frac{1}{333.36})\\\\ln(\frac{P_2}{102})=4726.967(\frac{333.36-308.05}{333.36\times308.05})\\\\ln(\frac{P_2}{102})=4726.967(\frac{25.31}{333.36\times308.05})\\\\ln(\frac{P_2}{102})=4726.967(\frac{25.31}{102691.548})\\\\ln(\frac{P_2}{102})=1.165

Taking inverse log both side we get,

\frac{P_2}{102}=e^{1.165}\\\\P_2=102\times 3.20\ mmHg\\P_2=327\ mmHg

8 0
3 years ago
Calculate the heat required to melt 7.35 g of benzene at its normal melting point. Heat of fusion (benzene) = 9.92 kJ/mol Heat =
grigory [225]

Answer:

The heat required to melt 7.35 g of benzene at its normal melting point is 934.8 Joules.

The heat required to vaporize 7.35 g of benzene at its normal melting point is 2,893 Joules.

Explanation:

Mass of benzene = 7.35 g

Moles of benzene = \frac{7.35 g}{78 g/mol}=0.09423 mol

Heat fusion of benzene,\Delta H_{fus} = 9.92 kJ/mol

1) Heat required to melt 7.35 g of benzene at its normal melting point = Q

Q=\Delta H_{fus}\times 0.09423 mol

=9.92 kJ/mol\times 0.09423 mol=0.9348 kJ=934.8 J

(1 kJ = 1000 J)

2) Heat vaporization of benzene,\Delta H_{vap} = 30.7 kJ/mol

Heat required to vaporize 7.35 g of benzene at its normal melting point = Q

Q=\Delta H_{Vap}\times 0.09423 mol

=30.7 kJ/mol\times 0.09423 mol=2.893 kJ=2,993 J

(1 kJ = 1000 J)

3 0
4 years ago
Which color has the highest frequency?
pantera1 [17]
Hello
The answer would be purple
6 0
3 years ago
Read 2 more answers
Based on the definitions of acid and base, identify the acid and base in this reaction. Then identify the spectator ion.
strojnjashka [21]

Answer:

Acid : H2O

Base : O2

Spectator Ions : K+

Explanation:

8 0
2 years ago
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