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Natalka [10]
3 years ago
15

what are simplified definitions of the following words"Synthesis, Decomposition, Single Replacement, or Double Replacement"?

Chemistry
1 answer:
faust18 [17]3 years ago
8 0

Answer:

The Four Major Types of Reactions

Name General Reaction Pattern

Combination or synthesis A + B ----> AB

Decomposition AB ----> A + B

Substitution or Single Replacement A + BC ----> B + AC

Metathesis or Double Displacement AB + CD ----> AD + CB

Combination or Synthesis Reactions Two or more reactants unite to form a single product.

S + O2 ---------> SO2

sulphur oxygen sulphur dioxide

2 S + 3 O2 ---------> 2 SO3

sulphur oxygen sulphur trioxide

2 Fe + O2 ---------> 2 FeO

iron oxygen iron (II) oxide

Decomposition Reactions A single reactant is decomposed or broken down into two or more

products.

CaCO3 ----------> CaO + CO2

calcium carbonate calcium oxide carbon dioxide

2 H2O -----------> 2 H2 + O2

water hydrogen oxygen

2 KClO3 -----------> 2 KCl + 3 O2

potassium chlorate potassium chloride oxygen

Substitution or Single Replacement Reactions A single free element replaces or is substituted for one of the elements in a compound. The free element is more reactive than the one its replaces.

Zn + 2 HCl ----------> H2 + ZnCl2

zinc hydrochloric acid hydrogen zinc chloride

Cu + 2 AgNO3 -----------> 2 Ag + Cu(NO3)2

copper silver nitrate silver copper (II) nitrate

H2 + 2 AgNO3 -----------> 2 Ag + 2 HNO3

hydrogen silver nitrate silver nitric acid

2 Na + 2 H2O -----------> 2 NaOH + H2

sodium water sodium hydroxide hydrogen

Metathesis or Double Displacement Reactions This reaction type can be viewed as an "exchange of partners." For ionic compounds, the positive ion in the first compound combines with the negative ion in the second compound, and the positive ion in the second compound combines with the negative ion in the first compound.

HCl + NaOH -----------> NaCl + HOH

hydrochloric sodium sodium water

acid hydroxide chloride

BaCl2 + 2 AgNO3 ----------> 2 AgCl + Ba(NO3)2

barium silver silver barium

chloride nitrate chloride nitrate

(precipitate)

CaCO3 + 2 HCl -----------> CaCl2 + H2CO3

calcium hydrochloric calcium carbonic

carbonate acid chloride acid

Explanation:

The vast number of chemical reactions can be classified in any number of ways. Under one scheme they can be categorized either as oxidation-reduction (electron transfer) reactions or non-oxidation-reduction reactions. Another completely different but common classification scheme recognizes

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enyata [817]

Answer:

Boron is Nonmetal

Explanation:

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3 0
3 years ago
How is Earth's surface most likely to change when a river flows across a steep landscape over time?
ANTONII [103]

Answer:c

Explanation:

A valley will be carved out due to erosion.

4 0
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Consider the addition of NaCl to the ice-water mix in Part II. Which of the following statements is TRUE?
Sati [7]
B is correct

salt lowers the freezing point of water (colligative property) by lowering the interaction and intermolecular forces between water molecules
6 0
3 years ago
Two samples of the same compound are compared. what does the data represent? sample 1: 24.22 g carbon and 32.00 g oxygen sample
goblinko [34]

According to law of definite proportion:

In a compound, elements are always arranged in fixed ratio by mass.

Here, sample 1 has 23.22 g Carbon and 32.00 g Oxygen.

Converting mass into number of moles:

Molar mass of carbon is 12 g/mol and that of oxygen is 16 g/mol thus,

n_{C}=\frac{m_{C}}{M_{C}}=\frac{24.22 g}{12 g/mol}\approx 2 mol

Similarly, number of moles of oxygen will be:

n_{O}=\frac{m_{O}}{M_{O}}=\frac{32 g}{16 g/mol}=2 mol

The ratio of number of moles of carbon and oxygen will be:

C:O=n_{C}:n_{O}=2:2=1:1

Therefore, formula of compound will be CO.

Sample 2:

It has 36.22 g Carbon and 48.00 g Oxygen.

Converting mass into number of moles:

Molar mass of carbon is 12 g/mol and that of oxygen is 16 g/mol thus,

n_{C}=\frac{m_{C}}{M_{C}}=\frac{36.22 g}{12 g/mol}\approx 3 mol

Similarly, number of moles of oxygen will be:

n_{O}=\frac{m_{O}}{M_{O}}=\frac{48 g}{16 g/mol}=3 mol

The ratio of number of moles of carbon and oxygen will be:

C:O=n_{C}:n_{O}=3:3=1:1

The formula of compound will be CO.

Therefore, it is proved that carbon and oxygen are present in fixed ratios in both the samples.


4 0
3 years ago
# of protons = 48 <br><br> Cadmium <br> Titanium <br> Oxygen <br> Krypton
Dafna11 [192]

Answer:

Cadmium +p= 48

Titanium p=22

Oxygen p=8

Krypton p=36

So the answer is Cadmium which has #48 protons

Explanation:

7 0
3 years ago
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