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n200080 [17]
3 years ago
9

If the area of the rectangle below is 42 inches, find the value of x

Mathematics
2 answers:
ArbitrLikvidat [17]3 years ago
7 0

Answer:

A = LW

LW = A

(x + 3)(x - 8) = 42

x^2 - 8x + 3x - 24 = 42

x^2 - 5x - 66 = 0

(x - 11)(x + 6) = 0

x - 11 = 0    or    x + 6 = 0

x = 11         or    x = -6

The length of the side of a rectangle cannot be a negative number, so we discard the negative answer, x = -6.

Answer: x = 11

Step-by-step explanation:

Just re-posted for some points.

vova2212 [387]3 years ago
6 0
A = LW

LW = A

(x + 3)(x - 8) = 42

x^2 - 8x + 3x - 24 = 42

x^2 - 5x - 66 = 0

(x - 11)(x + 6) = 0

x - 11 = 0    or    x + 6 = 0

x = 11         or    x = -6

The length of the side of a rectangle cannot be a negative number, so we discard the negative answer, x = -6.

Answer: x = 11
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\displaystyle\\Answer:\ x=\sqrt{2}\ \ \ \ \ x=-\sqrt{2}\ \ \ \ \ x=\frac{ln5}{2}

Step-by-step explanation:

5x^2-x^2e^{2x}+2e^{2x}=10

Let:\ x^2=t  \ \ \ \ \ e^{2x}=v\\Hence,\\5t-tv+2v^2=10\\5t-tv+2v^2-10=10-10\\5t-tv-10+2v^2=0\\t(5-v)-2(5-v)=0\\(5-v)(t-2)=0\\5-v=0\\5-v+v=0+v\\5=v\\5=e^{2x}

<em>Prologarithmize both parts of the equation:</em>

ln5=lne^{2x}\\ln5=2x*lne\\ln5=2x*1\\ln5=2x\\

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\displaystyle\\x=\frac{ln5}{2}

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