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svetlana [45]
3 years ago
14

The force that attracts objects towards another object.

Physics
1 answer:
Marizza181 [45]3 years ago
5 0

Answer:

Gravity Force

Gravity Force(also known as Weight) The force of gravity is the force with which the earth, moon, or other massively large object attracts another object towards itself. By definition, this is the weight of the object <em><u>your welcome </u></em>

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Which of the following statements is correct A. College degree isn't as important as it was in the past b. Over time, I can earn
julia-pushkina [17]

Answer:

I'd say C is the answer they want, though my pedantic side wants to argue for B being true as well.

3 0
3 years ago
What is the weight of a 5.00 kg object on Earth? Assume g=9.81 m/s^2.
Softa [21]

<em>weight = (mass) x (gravity)</em>

Weight = (5.00 kg) x (9.81 m/s²)

weight = (5.00 x 9.81) (kg-m/s²)

<em>Weight = 49.05 Newton</em>

7 0
3 years ago
How many electrons would it take to equal the mass of a proton? Use two significant figures.
mezya [45]
<span>How many electrons would it take to equal the mass of a proton:
Here's one way of finding the value of it:
=> number of electrons is equivalent to 1 proton.
Let's have an example.
1.6726*10 -24g
_______________
     1 proton
______________
9.109*10- ^28g
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1 electron

Based on the given example above, the electrons is 1 839 per 1 proton.
It's about 1800 electrons/proton.</span>
5 0
4 years ago
If 90 grams of gold has a volume of 5 cm3, calculate the density (include the units and show your work or you get no credit
ehidna [41]

Answer:

The density of gold is of 18 grams per cm3.

Explanation:

The mass density of a homogeneous material expresses how much mass of that material is present in a given volume. Since the density of an object is obtained by dividing its mass by its volume, to obtain the density of gold, its 90 grams of mass must be divided by its 5 cm3 volume, performing the following calculation:

90/5 = X

18 = X

Thus, the density of gold is 18 grams per cm3.

6 0
3 years ago
A laser beam is incident on two slits with a separation of 0.195 mm, and a screen is placed 5.30 m from the slits. If the bright
kumpel [21]

Answer:

λ = 596 nm.

Explanation:

Fringe width = λ D / d

λ is wave length , D is screen distance and d is slit separation.

Putting the values

1.62 x 10⁻² =(  λ x 5.3 ) / .195 x 10⁻³

\lambda=\frac{1.62\times10^{-2}\times195\times10^{-6}}{5.3}

λ = 596 nm.

8 0
3 years ago
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