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vagabundo [1.1K]
3 years ago
13

Which electrons participate in chemical bonding

Chemistry
2 answers:
Fofino [41]3 years ago
4 0
The name given to the specific electrons that participate in chemical bonding are called valence electrons.
N76 [4]3 years ago
3 0

Answer: valence electrons

Explanation:-

Chemical bond is formed either by sharing of electrons or transfer of valence electrons.

Chemical reactivity is defined as the tendency of an element to loose or gain electrons which are present in the last or valence shell which are called as valence electrons.

A covalent bond is formed when an element shares its valence electron with another element. This bond is formed between two non metals.

HF is formed by sharing of valence electrons of hydrogen and fluorine to complete their octet.

An ionic bond is formed when an element completely transfers its valence electron to another element. The element which donates the electron is known as electropositive element and forms a positively charged ion called as cation. The element which accepts the electrons is known as electronegative element and forms a negatively charged ion called as anion.

Thus valence electrons participate in chemical bonding.

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There are three naturally occurring isotopes of the hypothetical element hilarium 45Hi, 46Hi, and 48Hi. The percentages of these
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Answer:

46.761g/mol

Explanation:

Given parameters:

Element = Hilarium , Hi

Isotopes: Hi- 45, Hi-46 and Hi- 48

Natural abundance of Hi-45 = 18.3%

                                     Hi-46 = 34.5%

                                     Hi-48 = 47.2%

Unknown:

Atomic weight of naturally occurring Hilarium = ?

Solution:

Isotopes have been studied extensively by mass spectrometry. The method is used to determine the proportion/percentage/fraction by which each of the isotopes of an element occurs in nature. The proportion is called geonormal abundance. From this we can calculate the atomic weight of an element.

 We can use the expression below to find this value:

       Atomic weight = m₄₅α₄₅ + m₄₆α₄₆ + m₄₈α₄₈

    m is the atomic mass of each isotope and α is the abundance

Atomic weight = (45 x \frac{18.3}{100} ) + (46 x  \frac{34.5}{100} ) + (48 x  \frac{47.2}{100})

Atomic weight of Hi = 8.235 + 15.870 +  22.656 = 46.761g/mol

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What are Dobereiner's Traids ?​
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