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3 years ago

Which two values for `DeltaG` and E°cell correctly indicate a spontaneous reaction?

1 answer:

4 0

Well as an spontaneous reaction will have a negative gibbs free energy (delta g) and a positive e cell and also the E cell is also measured in V, then your answer is the first one: ΔG = –295kJ, E°cell = +1.53 v. Hope this works

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3 years ago

QUESTION 3 What is different between an ionic bond and a covalent bond? An ionic bond is a bond between charged atoms, while a c

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Q) What is different between an ionic bond and a covalent bond?

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3 years ago

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When KOH dissolved in ethanol, what is the intermolecular attraction between OH- ions and C2H5OH molecules

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2 years ago

PLZ ANSWER WILL GIVE BRAINEST Based on the information in the table, which elements are most likely in the same periods of the p

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Answer:

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Explanation:

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3 years ago

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Suppose that Daniel has a 3.00 3.00 L bottle that contains a mixture of O 2 O2 , N 2 N2 , and CO 2 CO2 under a total pressure of

Alenkinab [10]

Answer:

Partial pressure O₂ → 2.74 atm

Explanation:

Let's analyse the data given:

Volume → 3L

In the bottle there is a mixture of gases that contains, O₂, N₂ and CO₂.

Total pressure is 4.80 atm

Let's apply the Ideal Gases Law to determine the total moles of the mixture

P . V = n . R. T

4.80 atm . 3L = n . 0.082 . 273K

n = 4.80 atm . 3L / 0.082 . 273K → 0.643 moles

We apply the concept of mole fraction:

Mole fraction of a gas X = moles of gas X / Total moles

Mole fraction of a gas X = Partial pressure X / Total pressure

In a mixture, sum of mole fraction of each gas = 1

We determine mole fraction of N₂ → 0.230 / 0.643 = 0.357

We determine mole fraction of CO₂ → 0.350 atm / 4.80 atm = 0.0729

1 - mole fraction N₂ - mole fraction CO₂ = mole fraction O₂

1 - 0.357 - 0.0729 = 0.5701 → mole fraction O₂

We replace in the formula: Mole fraction O₂ = Partial pressure O₂ / 4.80 atm

0.5701 . 4.80 atm = Partial pressure O₂ → 2.74 atm

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2 years ago

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