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melamori03 [73]
2 years ago
6

Ice

Chemistry
1 answer:
fomenos2 years ago
8 0
I think I it’s gonna be C.
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What formula do you use to calculate the heat in a endothermic reaction?
leva [86]
Reactants + Energy → Products
I guess this is the answer
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4 0
3 years ago
How many molecules are there in 2.30g of NH3
Vinil7 [7]

Answer:

8.13x10^22 molecules

Explanation:

We can use the Avogadro's number(6.022 x 10^23 units / mole)

2.30 g NH3 (1 mol / 17.03 g ) (6.022 x 10^23 molecules / 1 mol ) = 8.13x10^22 molecules

Hope this helps! Feel free to ask any questions!

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2 years ago
Cora, an electrician, wraps a copper wire with a thick plastic coating. What is she most likely trying to do?.
Vinil7 [7]

Answer:

SHE IS INSULATING THE WIRE SO THAT NO ONE GETS SHOCKED IF THEY ACCIDENTALLY TOUCH IT

7 0
1 year ago
The mobile electrons of a pure metal are <br> called what
olchik [2.2K]

Answer:

This means that the metal is more properly viewed as an array of positive ions surrounded by a “sea of mobile valence electrons.” Electrons which are capable of moving freely throughout the empty orbitals of the metallic crystal are called delocalized electrons (Figure below).

5 0
3 years ago
what is the order of decreasing bond length for a C-C bond composed of the following molecular orbitals?I. sp^3 - sp^3II. sp^2 -
skelet666 [1.2K]

Answer:

The decreasing order of bond length in the carbon - carbon bonds will be:

C-C>C=C>C\equiv C

Explanation:

Bond length is defined as average distance between two nuclei of  bonded atoms in a molecule.Bond length is inversely  proportional to the number of bonds present between two atoms.

\text{Bond length} \propto \frac{1}{\text{Number of bonds}}...[1]

Bond energy is defied as amount of energy required to break apart the bond of 1 mole of molecule into their individual atom. Bond energy is directly proportional to the number of bonds present between two atoms.

\text{Bond Energy} \propto \text{Number of bonds}..[2]

From [1] and [2]:

\text{Bond length} \propto \frac{1}{\text{Bond energy}}

C-C: sp_3 hybridized

C=C: sp_2 hybridized

C\equiv C: sp hybridized

Extent of overlapping of orbitals in these hybridization;

C\equiv C> C=C > C-C

Higher the overlapping of orbital more closer will be both atoms to each other and shorter will be the bond lenght.

So, the decreasing order of bond length in the carbon - carbon bonds will be:

C-C>C=C>C\equiv C

8 0
2 years ago
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