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Bess [88]
3 years ago
5

The molarity of a 4.200 L solution is 1.230 M Na2CO3. What is the mass of Na2CO3

Chemistry
1 answer:
Lerok [7]3 years ago
7 0

Answer:

547.5g

Explanation:

To get the mass, you need moles.

moles = (molarity)(Liters)

moles = (1.230M)(4.200L) = 5.166 moles Na2CO3

Now, just use stoichiometry

molar mass of Na2CO3 = 2(mass of Na) + (mass of C) + 3(mass of O)

= 2(22.9) + 12.01 + 3(16) = 105.99g/mol

5.166moles(105.99g/mol)

= 547.544

But, the measurements given had 4 significant figures, so in chemistry we write:

547.5g

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Explanation:

Equation of reaction:

2HCl → H₂ + Cl₂

From the equation of reaction,

From ideal gas equation,

PV = nRT

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R = ideal gas constant

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X moles HCl = 0.5mole

X = (2 × 0.5) / 1

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