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Bess [88]
3 years ago
5

The molarity of a 4.200 L solution is 1.230 M Na2CO3. What is the mass of Na2CO3

Chemistry
1 answer:
Lerok [7]3 years ago
7 0

Answer:

547.5g

Explanation:

To get the mass, you need moles.

moles = (molarity)(Liters)

moles = (1.230M)(4.200L) = 5.166 moles Na2CO3

Now, just use stoichiometry

molar mass of Na2CO3 = 2(mass of Na) + (mass of C) + 3(mass of O)

= 2(22.9) + 12.01 + 3(16) = 105.99g/mol

5.166moles(105.99g/mol)

= 547.544

But, the measurements given had 4 significant figures, so in chemistry we write:

547.5g

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Would aluminum be as useful as food wrapping if it had a much lower melting point? Explain your answer.
Salsk061 [2.6K]

The correct answers are as follows:

1. Aluminium will not be useful as food wrapping if it has a much lower melting point.

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2. When bleach react with fabric dye chemical change occur in the fabric.

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4 0
3 years ago
I'm in a rush please help
Alexeev081 [22]

16) <

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18) =

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4 0
3 years ago
Dissolution of wax in kerosene
yanalaym [24]

Answer:

the first answer is correct don't forget you can use quizzlet app to

8 0
2 years ago
Ascorbic acid, or vitamin C (C6H8O6, molar mass = 176 g/mol), is a naturally occurring organic compound with antioxidant propert
nydimaria [60]

Answer : 50.69 mg of ascorbic acid does not meet the daily requirement.

Solution : Given,

Molar mass of Ascorbic acid = 176 g/mole

Moles of Ascorbic acid = 2.88\times 10^{-4}moles

Formula used :

Moles=\frac{Mass}{\text{ Molar mass}}

or, \text{ Mass of ascorbic acid}=\text{ Moles of ascorbic acid}\times \text{ Molar mass of ascorbic acid}

Now put all the given values in this formula, we get the mass of ascorbic acid.

\text{ Mass of ascorbic acid}=(2.88\times 10^{-4}moles)\times (176g/mole)=0.050688g=50.69mg

Conversion : (1g=1000mg)

As per question, a healthy adult’s daily requirement of vitamin C is 70-90 mg. But calculate mass of vitamin C is 50.69 mg. So, 50.69 mg of ascorbic acid does not meet the daily requirement.

5 0
3 years ago
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