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sergeinik [125]
3 years ago
12

A bobsled has a momentum of 4000 0 kg* m/s to the south. Friction on the track reduces its momentum to 500 kg* m/s to the south.

What impulse is applied to the bobsled by the friction?
A. 6500 kg* m/s north

OB. 1500 kg* m/s south O

C. 6500 kg* m/s south

O 1500 kg* m/s north
Chemistry
2 answers:
In-s [12.5K]3 years ago
7 0

Answer: B

Explanation: 4000- 1500

faltersainse [42]3 years ago
6 0
The correct answer is c
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1. 4FeCl3 + 3O2 → 2Fe2O3 + 6Cl2

2. 6 moles of Cl2

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1. The balanced equation for the reaction. This is illustrated below:

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2. Determination of the number of mole of Cl2 produce when 4 moles of FeCl3 react with 4 moles. To obtain the number of mole of Cl2 produced, we must determine which reactant is the limiting reactant.

This is illustrated below:

From the balanced equation above,

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