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expeople1 [14]
3 years ago
6

A tube with a cap on one end, but open at the other end, has a fundamental frequency of 130.8 Hz. The speed of sound is 343 m/s

(a) If the cap is removed, what is the new fundamental frequency of the tube
Physics
1 answer:
sergey [27]3 years ago
8 0

Answer:

Y = V / f      where Y equals wavelength

4 Y1 = V / f1       for a closed pipe the wavelength is 1/4 the length of the pipe

2 Y2 = V / f2   for the open pipe the wavelength is 1/2 the length of the pipe

Y1 / Y2 = 2 = f2 / f1      dividing equations

f2 = 2 f1  

the new fundamental frequency is 2 * 130.8 = 261.6

(The new wavelength is 1/2 the original wavelength so the frequency must double to produce the same speed.

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Consider the following three statements: (i) For any electro-magnetic radiation, the product of the wavelength and the frequency
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A and B

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58.5 m

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