A tube with a cap on one end, but open at the other end, has a fundamental frequency of 130.8 Hz. The speed of sound is 343 m/s
1 answer:
You might be interested in
This question can be solved with the help of the equations of motion.
A) The Frisbee will remain in the air for "5.87 s".
B) The frisbee will go "29.4 m" down the range.
A)
To calculate the time, the frisbee will remain in the air, we will use the second <em><u>equation of motion</u></em>, for the vertical motion.
where,
h = height = 169.2 m
vi = initial velocity's vertical component = 0 m/s
g = acceleration due to gravity = 9.81 m/s²
t = time = ?
Therefore,
<u>t = 5.87 s</u>
<u />
B)
Now, we will calculate the horizontal range by applying the equation for constant motion. Because the velocity in the horizontal direction will remain constant due to no air resistance
s = vt
where,
s = horizontal range = ?
v= initial velocity's horizontal component = 5 m/s
t = time = 5.87 s
Therefore,
s = (5 m/s)(5.87 s)
<u>s = 29.4 m</u>
<u />
Learn more about <em><u>equations of motion</u></em> here: