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2 years ago

What's the formula to find out power

1 answer:

3 0

In general,

   Power = (energy moved) / (time to move the energy) .

If it's mechanical power, then

   Power = (work done) / (time to do the work) .

If it's electrical power, then it can be any one of these:

   Power = (volts) x (amperes)

   Power = (volts)² / (resistance, ohms)

   Power = (amperes)² x (resistance, ohms) .

Whatever kind of energy you're dealing with, power always
turns out to be

(amount of energy produced, used, or moved)
divided by
(time taken to produce, use, or move the energy) .

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A thin, rectangular sheet of metal has mass M and sides of length a and b. Find the moment of inertia of this sheet about an axi

slega [8]

We divide the thin rectangular sheet in small parts of height b and length dr. All these sheets are parallel to b. The infinitesimal moment of inertia of one of these small parts is
$dI =r^2*dm$
where $dm =M(b*dr)/(ab)$
Now we find the moment of inertia by integrating from $-a/2$ to $a/2$
The moment of inertia is
$I= \int\limits^{-a/2}_{a/2} {r^2*dm} = M \int\limits^{-a/2}_{a/2} r^2(b*dr)/(ab)=(M/a)(r^3/3)$ (from (-a/2) to $I=(M/3a)(a^3/8 +a^3/8)=(Ma^2)/12$ (a/2))

4 0

3 years ago

The component of the external magnetic field along the central axis of a 78-turn circular coil of radius 34.0 cm decreases from

grigory [225]

Answer:

Induced current, I = 18.88 A

Explanation:

It is given that,

Number of turns, N = 78

Radius of the circular coil, r = 34 cm = 0.34 m

Magnetic field changes from 2.4 T to 0.4 T in 2 s.

Resistance of the coil, R = 1.5 ohms

We need to find the magnitude of the induced current in the coil. The induced emf is given by :

$\epsilon=-N\dfrac{d\phi}{dt}$

Where

$\dfrac{d\phi}{dt}$ is the rate of change of magnetic flux,

And $\phi=BA$

$\epsilon=-NA\dfrac{dB}{dt}$

$\epsilon=-78\times \pi (0.34)^2\dfrac{(0.4-2.4)}{2}$

$\epsilon=28.32\ V$

Using Ohm's law, $\epsilon=I\times R$

Induced current, $I=\dfrac{\epsilon}{R}$

$I=\dfrac{28.32}{1.5}$

I = 18.88 A

So, the magnitude of the induced current in the coil is 18.88 A. Hence, this is the required solution.

5 0

2 years ago

A volumetric flow rate of 2 m^3/ s of liquid water is to be pumped from sea level to an elevation of 1200 m. Taking the density

exis [7]

Answer:

power requirement is 23.52 × $10^{6}$ W

Explanation:

given data

flow rate q = 2 m³/s

elevation h = 1200 m

density of the water ρ = 1000 kg/m³

to find out

power requirement

solution

we will get power by the power equation that is

power = ρ× Q× g× h ...................1

put here all value we get power

power = ρ× Q× g× h

power = 1000 × 2 × 9.8 × 1200

power = 23.52 × $10^{6}$

so power requirement is 23.52 × $10^{6}$ W

6 0

3 years ago

What is 1 + 1 - 1 + 2 - 1 - 1<br>This is just to get answers

geniusboy [140]

Answer:

answer is 1

Explanation:

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2 years ago

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Sound is an example of a ____ Wave.

sesenic [268]

Answer:

Mechanical Waves

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7 0

2 years ago

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