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hjlf
3 years ago
13

Imagine that treble sounds could travel at 400 m/s, but bass sounds traveled at only 300 m/s. If sound actually behaved that way

, and you were listening to a brass band from a distance of 120m, how much delay would you hear between trumpet and tuba notes when they begin a chord together?
Physics
1 answer:
kirza4 [7]3 years ago
4 0

Answer:

\Delta t = 0.1s

Explanation:

We need to calculate the difference between the times the waves from the bass sounds (t_b) and treble sounds (t_t) take to reach us, that is, \Delta t = t_b-t_t.

Since v=\frac{d}{t}, then t=\frac{d}{v} and we can write:

\Delta t = t_b-t_t=\frac{d}{v_b} - \frac{d}{v_t}=d(\frac{1}{v_b} - \frac{1}{v_t})=(120m)(\frac{1}{300m/s} - \frac{1}{400m/s})=0.1s

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3 years ago
A 35 kg boy is riding a 65 kg go-cart. He pushes on the gas pedal, causing the cart to accelerate at 5 m/s2. Use the equation F
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Answer:

\boxed {\boxed {\sf 500 \ Newtons }}

Explanation:

The equation for force is given:

F=m*a

First, we must find the total mass, which is the sum of the boy's mass and the go-cart's mass.

  • total mass= boy's mass + go cart's mass

The boy's mass is 35 kilograms and the go cart's is 65 kilograms.

  • total mass= 35 kg+ 65 kg=100 kg

Now we know the total mass and the acceleration.

m= 100 \ kg \\a= 5 \ m/s^2

Substitute the values into the formula.

F=100 \ kg * 5 \ m/s^2

Multiply.

F= 500 \ kg*m/s^2

  • 1 kilograms meter per square second is equal to 1 Newton.
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F= 500 \ N

The force exerted by the go cart engine is <u>500 Newtons.</u>

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2 years ago
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Answer:

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r is the distance measured from the center of the Earth

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       Em₀ =  Em_{f}

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       v² = 2 G M (1 /  R_{e} – 1 / r)

       v = √ 2GM (1 / R_{e} – 1 / r)

The escape velocity is that necessary to take the rocket to an infinite distance (r = ∞), whereby 1 /∞ = 0

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