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3 years ago

6

A yellow ball with a mass of 2 kg is rolling across the floor at 3 m/s. A red ball with a mass of 3 kg is rolling across the sam

e floor at 3 m/s. Which ball has greater kinetic energy, and why?

2 answers:

marta [7]3 years ago

7 0

Answer:

mass of 3 kg has greater kinetic energy.

Olin [163]3 years ago

3 0

Answer: The red ball has greater kinetic energy, because it has a greater mass.

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"a musical tone sounded on a piano has a frequency of 261.6 hz and a wavelength of 1.31 m. what is the speed of the sound wave

Andreyy89

To solve this question, we use the wave equation which is:
C=f*λ
where:
C is the speed;
f is the frequency;
λ is the wavelength
So in this case, plugging in our values in the problem. This will give us:
C = 261.6Hz × 1.31m
= 342.696 m/s is the answer.

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3 years ago

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We want to find how much charge is on the electrons in a nickel coin. Follow this method. A nickel coin has a mass of about 5.7

Aleksandr-060686 [28]

<span>5.6x10e22 atoms
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3 years ago

Consider a ball of 0.22 kg, initially at rest, is dropped from an initial height of 1.80 m. It rebounds back after colliding wit

I am Lyosha [343]

Answer:

The impulse on the ball delivered by the floor is 2.52 kg-m/s.

Explanation:

Given that,

Mass of the ball, m = 0.22 kg

It is dropped from an initial height of 1.80 m. It rebounds back after colliding with the floor to a final height of 1.50 m. Initial velocity and final velocity can be calculated using conservation of energy as :

$u=\sqrt{2gh} \\\\u=\sqrt{2\times 10\times 1.8} \\\\u=6\ m/s$

Final velocity,

$v=\sqrt{2gh'} \\\\v=\sqrt{2\times 10\times 1.5} \\\\v=5.47\ m/s$

As the ball rebounds, v = -5.47 m/s

We need to find the impulse on the ball delivered by the floor. We know that impulse is equal to the change in momentum as follows :

$J=m(v-u)\\\\J=0.22\times ((-5.47)-6)\\\\J=-2.52\ kg-m/s$

So, the impulse on the ball delivered by the floor is 2.52 kg-m/s.

7 0

3 years ago

A series RLC circuit consists of a 52.0 Ω resistor, a 4.80 mH inductor, and a 330 nF capacitor. It is connected to an oscillator

Tju [1.3M]

Answer:

(G) 75.11 ohm

(H) 0.08 A

(I) 46.2 degree

Explanation:

R = 52 ohm

L = 4.8 m H = 4.8 x 106-3 H

C = 330 nF = 330 x 10^-9 F

Vo = 6 V

(G)

f = 5000 Hz

Let the impedance is Z.

$X_{L}= 2 \pi fL = 2 \times 3.14\times 5000\times 4.8\times 10^{-3}=150.72 ohm$

$X_{c}= \frac{1}{2 \pi fC}=\frac{1}{2\times 3.14\times 5000\times 330\times 10^{-9}}=96.51 ohm$

$Z=\sqrt{R^{2}+\left ( X_{L}-X_{c} \right )^{2}}$

$Z=\sqrt{52^{2}+\left (150.72-96.51)^{2}}=75.11 ohm$

(H) Let Io be the peak current

$I_{0}=\frac{V_{0}}{Z}=\frac{6}{75.11}=0.0798 A = 0.08 A$

(I) Let Ф be the phase angle

$tan\phi = \frac{X_{L}-X_{C}}{R}$

$tan\phi =\frac{150.72-96.51}}{52}=1.0425$

Ф = 46.2 degree

4 0

3 years ago

As altitude increases, what happens to air pressure?

Mashcka [7]

Answer:

It decreases

Explanation:

The air pressure tends to be higher on the places with the lowest altitudes, and lower at the places with higher altitudes. Basically, the air pressure is the wight of the air, and since the air is denser and heavier at the lower altitudes, the air pressure is higher, while on the higher altitudes the air is less dense, thus the air pressure is lower. So in practice we can expect that the air pressure in a low valley will be higher than the air pressure at the top of higher mountain.

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3 years ago

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