To solve this problem, we know that:
1 psi = 6894.76 Pa
1 lb / ft^2 = 47.88 Pa
Therefore:
a. 1500 x 10^3 Pa * (1 lb / ft^2 / 47.88 Pa) = 31,328.32 lb
/ ft^2
b. 1500 x 10^3 Pa * (1 psi / 6894.76 Pa) = 217.56 psi
Answer:
s = 45 m
Explanation:
The velocity given in the question is uniform. Hence, the formula for the uniform velocity shall be used here. The formula is given as follows:

where,
s = distance traveled away from the brother = ?
v = constant speed = 3 m/s
t = time taken = (0.25 min)(60 s/1 min) = 15 s
Therefore, using these values in the formula we get:

<u>s = 45 m</u>
Answer:
An applied force is a force that is applied to an object by a person or another object. If a person is pushing a desk across the room, then there is an applied force acting upon the object. The applied force is the force exerted on the desk by the person.
It states that the rate of change of velocity of an object is directly proportional to the force applied and takes place in the direction of the force. It is summarized by the equation: Force (N) = mass (kg) × acceleration (m/s²). Thus, an object of constant mass accelerates in proportion to the force applied.
Answer:
The value of the constant k is 2
Explanation:
We have the equation of the velocity
= kt² , where k
is constant and t is the time in second
The particle's position at
= 0 is
= -9 m
The particle's position at
= 3 s is
= 9 m
We need to find the value of the constant k
The relation between the velocity and the displacement in a particular
time is x = 
Remember in integration we add power by 1 and divide the expression
by the new power
→ x = 
c is the constant of integration to find it substitute the initial value of x
and t in the equation of x
→
= 0 ,
= -9 m
→ -9 =
k (0)³ + c
→ -9 = c
Substitute the value of c in the equation of x
→ x =
k t³ - 9
To find k substitute the values of
= 3 s ,
= 9 m
→ 9 =
k (3)³ - 9
→ 9 =
(27) k - 9
→ 9 = 9 k - 9
Add 9 to both sides
→ 18 = 9 k
Divide both sides by 9
→ k = 2
<em>The value of the constant k is 2</em>
Answer:
v= 300 m/s
Explanation:
Given that
altitude ,h= 4500 m
The mass ,m = 3 kg
Lets take acceleration due to gravity , g= 10 m/s²
The speed before impact at sea level = v
Initial speed ,u = 0 m/s
We know that
v²=u²+2 g h
v=final speed
u=initial speed
h=height
Now by putting the values in the above equation
v² = 0²+ 2 x 10 x 4500
v²=90000
v= 300 m/s
Therefore the speed at sea level will be 300 m/s.