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klasskru [66]
3 years ago
9

Calculate the density of a material that has a mass of 52.457 g and a volume of 13.5 cm3

Physics
1 answer:
Sphinxa [80]3 years ago
8 0

Answer:

Density is 3.90g/cm3

Explanation:

Density = mass ÷ volume

= 52.457g ÷ 13.5cm3

= 3.885703704g/cm3

= 3.90g/cm3

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Answer:

♕ \large{ \red{ \tt{Step - By - Step \: Explanation}}}

☃ \underline{ \underline{ \blue{ \large{ \tt{G \: I \: V \: E\: N}}}}} :

  • Frequency ( f ) = 7 Hertz
  • Wavelength ( λ ) = 42m

♨ \underline {\underline{ \orange{ \large{ \tt{T \: O \:  \: F \: I \: N\: D}}}} }:

  • Wave velocity ( v )

☄ \underline{ \underline{ \large{ \pink{ \tt{S\: O \: L \: U \: T\: I \: O \: N}}}}}:

✧ \red{ \boxed{ \large{ \purple{ \sf{Wave \: velocity(v) = Frequency(f) \times Wavelength(λ)}}}}}

~Plug the known values and then multiply!

↦ \large{ \tt{7  \times 42}}

↦ \boxed{ \boxed{ \large{ \bold{ \tt{294 \: m {s}^ {- 1} }}}}}

☥ \large{ \boxed{ \boxed{ \large{ \tt{Our \: Final \: Answer :  \underline{ \large{ \tt{294 \: m {s}^{ - 1}}}}}}}}}

---------------------------------------------------------------

❁ \underline{ \large{  \red{ \tt{D\: E\: T \: A \: I \: L\: E \: D \:  \: I\: N \: F \: O}}}} :

  • Frequency ( f ) : The number of complete waves , set up in a medium in one second is called frequency of the wave. The SI unit of frequency is Hertz ( Hz ). For example : if a sound wave completes 15 compressions and 15 rarefactions in one second , it's frequency is 15 Hz.

  • Wavelength ( λ ) : The distance between two consecutive troughs or crests in a transverse wave or the distance between two consecutive compressions or rarefactions in a longitudinal wave us called wavelength. It is the distance travelled by a wave in a time equal to it's time period. It's SI unit is metre ( m ).

  • Wave velocity ( v ) : The velocity with which a wave propagates in a medium is called wave velocity. It's SI unit is m/s.

# KILL : Excuses

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4 0
3 years ago
Choose all the answers that apply. Oxygen is _____. transported by blood picked up in the alveoli released into the air by the l
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ANSWER:

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A wire is stretched between two posts. Another wire is stretched between two posts that are twice as far apart. The tension in t
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Answer: 996m/s

Explanation:

Formula for calculating velocity of wave in a stretched string is

V = √T/M where;

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M is the mass per unit length of the wire(m/L)

Since the second wire is twice as far apart as the first, it will be L2 = 2L1

Let V1 and V2 be the speed of the shorter and longer wire respectively

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V2 = √T/M2... 2

Since V1 = 249m/s, M1 = m/L1 M2 = m/L2 = m/2L1

The equations will now become

249 = √T/(m/L1) ... 3

V2 = √T/(m/2L1)... 4

From 3,

249² = TL1/m...5

From 4,

V2²= 2TL1/m... 6

Dividing equation 5 by 6 we have;

249²/V2² = TL1/m×m/2TL1

{249/V2}² = 1/2

249/V2 = (1/2)²

249/V2 = 1/4

V2 = 249×4

V2 = 996m/s

Therefore the speed of the wave on the longer wire is 996m/s

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