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Roman55 [17]
3 years ago
11

1. Describe the motion of an object with positive velocity and negative acceleration.2. Describe the motion of an object with ne

gative velocity and positive acceleration.3. Describe the motion of an object with negative velocity and negative acceleration.
Physics
1 answer:
densk [106]3 years ago
3 0

Answer:

The answer to the question above is explained below

Explanation:

Acceleration is the rate of change of velocity.  In other words, acceleration is a change in either speed or direction, or both. An object is accelerating if it is changing its velocity, and, the SI units for acceleration are m/s2 (meters per second squared).

Velocity is a vector, and it is the speed at which an object moves in one direction. So in other words, velocity is the displacement of an object with respect to time.

For question 1 "Describe the motion of an object with positive velocity and negative acceleration"

<em><u>Answer to question 1</u></em>

A body moving in the positive direction has a positive velocity. While, a body can have negative acceleration, if the acceleration is in the opposite direction to the velocity of that body. So, addition or subtraction from the value of velocity is dependent on the direction of the acceleration. A negative acceleration means there will be subtraction from the value of the velocity.

For question 2 "Describe the motion of an object with negative velocity and positive acceleration."

<em><u>Answer to question 2</u></em>

An object which moves in the negative direction has a negative velocity. If the object is slowing down then its acceleration is directed in the opposite direction as its motion which leads to a positive acceleration. A negative velocity and a positive acceleration implies for example, an object going in negative direction whose speed is getting reduced.

For question 3 "Describe the motion of an object with negative velocity and negative acceleration."

<em><u>Answer to question 3</u></em>

The motion of an object where velocity and acceleration are both negative, the object experience an increase in speed, meaning the acceleration is in the same direction as the velocity.

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3 years ago
An inductor in an LC circuit has a maximum current of 2.4 A and a maximum energy of 56 mJ.
Harrizon [31]

Answer:

The energy stored in the capacitor, when the current in the inductor is 1.2 A, is 41.6 mJ.

Explanation:

In a LC oscillating circuit, the energy is stored in the electric field (between the plates of the capacitor) and in the magnetic field (surrounding the wires of the inductor).

At any time, the sum of both energies can be expressed as follows:

E = 1/2 Q² / C   +  1/2 L I²

In this type of circuit, energy oscillates, which means that it is exchanging between both fields all time.

When the capacitor is completely discharged, all the energy is stored in the magnetic field, and at that time, the current is maximum.

The total energy, when I is maximum, can be written as follows:

E = 1/2 L I² (1)

In our case, when I= 2.4A, E= 56 mJ.

So, we can find out the value of L, which will allow us to know the value of the magnetic energy at any time, having the value of the instantaneous current.

Solving for L in (1):

L = 2 *.56 mJ / (2.4)² A² = 20 mH

The next step is getting the value of the energy stored in the inductor, when I = 1.2 A, as follows:

Em = 1/2 *20 mH.* (1.2)² A² = 14.4 mJ

As the total energy must be always the same, i.e., 56 mJ, the energy stored in the capacitor, assuming no losses, must be the difference between the total energy and the one stored in the magnetic field:

Ec = 56 mJ - 14.4 mJ = 41.6 mJ

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3 years ago
Lucia raced her car on a raceway
denpristay [2]

Answer:

Good question to ask in physics, sir maam

8 0
2 years ago
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Answer:

A. potential energy is 258720 Joule

Explanation:

A.Gravitational potential energy is: PE = m × g × h

velocity =  15.33 m/s when the car reaches the bottom of the hill.

where, m = mass

            g = acceleration due to gravity

            h = height from the bottom of hill.

The potential energy is : m×g×h

                                     =(2200×9.8×12)

                                     =258720 Joule

B. at the bottom of the hill, the potential energy is converted into kinetic energy so PE at top = KE at bottom

                    kinetic energy= \frac{1}{2}(m*v^{2})

where v = velocity

          m= mass

therefore,               v=\sqrt\frac{2*K.E}{m} {}

                         or,  v=\sqrt{\frac{2*258720}{2200} }

                         or,   v=15.33 m/s

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An airplane is flying through a thundercloud at a height of 2 000 m. (this is a very dangerous thing to do because of updrafts,
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It is given that an<span> airplane is flying through a thundercloud at a height of 2000 m.
</span><span>
Since the parity of charges is opposite and the airplane lies between the two charges and both the electric fields are in the same direction at the plane. Therefore, the magnitudes of the electric field at the aircrafts will add up.
Now, check the image to see the calculations:

</span>

4 0
3 years ago
Read 2 more answers
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