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sammy [17]
3 years ago
15

An experiment was performed to determine how the amount of coffee grounds could affect the taste of coffee. The same kind of cof

fee, the same coffee pot, the same amount and type of water, the same cook time, and the same electrical sources were used (what is IV, DV, and one Control) *
Physics
1 answer:
Andru [333]3 years ago
7 0

Answer: Independent variable: The amount of coffee grounds.

Dependent variable: The taste of the coffee.

Controlled variables: The kind of coffee, the same percolator, the same amount and type of water, the same perking time, and the same electrical sources.

Explanation: In an experiment the independent variable is the variable that you change, the dependent variable is the variable that you are testing to see if it will change because of the change you made, and the controlled variables are the variables that stay the same.

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A box with mass m is dragged across a level floor with coefficient of kinetic friction μk by a rope that is pulled upward at an
Komok [63]

Answer:

a) F =  μk  mg Cosθ

b) F = 279.78 N

Explanation:

a) F = μk R

Based on the description in the question, the horizontal reaction is:

R = mg Cosθ

The force required to move the box with constant speed in terms of m, μk, θ, and g is :

F =  μk  mg Cosθ

b) If m = 90 kg

g = 9.8 m/s²

μk=0.35

θ = 25⁰

Force required to slide the 90-kg patient across a floor at constant speed by pulling on him at an angle of 25∘ above the horizontal will be:

F =  μk  mg Cosθ

F = 0.35 * 90 * 9.8 * cos25

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5 0
4 years ago
What is the displacement of this time velocity graph i need help asap
maw [93]

Answer:

b is the answer

Explanation:

because i did this before

3 0
4 years ago
A 6.0-kg object moving at 5.0 m/s collides with and sticks to a 2.0-kg object. After the collision the composite object is movin
gogolik [260]

Answer:

a) 23 m/s

Explanation:

  • Assuming no external forces acting during the collision, total momentum must be conserved, as follows:

       p_{o} = p_{f}  (1)

  • The initial momentum p₀, can be written as follows:

       p_{o} =  m_{1}  * v_{1o} + m_{2}* v_{2o} =   6.0 kg * 5.0 m/s + 2.0 kg * v_{2o}  (2)

  • The final momentum pf, can be written as follows:

        p_{f} = (m_{1} + m_{2} )* v_{f}  = 8.0 kg* (-2.0 m/s)  (3)

  • Since (2) and (3) are equal each other, we can solve for the only unknown that remains, v₂₀, as follows:

       v_{2o} = \frac{-6.0kg* 5m/s -8.0 kg*2.0m/s}{2.0kg}  = \frac{-46kg*m/s}{2.0kg} = -23.0 m/s  (4)

  • This means that the 2.0-kg object was moving at 23 m/s in a direction opposite to the 6.0-kg object, so its initial speed, before the collision, was 23.0 m/s.
6 0
3 years ago
Write one general properties of non contact force​
Gekata [30.6K]

Answer:    Gravitational force between the two masses does not depend on the medium separating two masses.

3 0
3 years ago
While it’s impossible to design a perpetual motion machine, that is, a machine that keeps moving forever, come up with ways to k
TEA [102]
It would be hard so many factors play a role in this angle kinetic potential energy gravity positioning height weight etc.to keep something as described moving as long as possible you'd have to build it heavily enough to balance out the momentum at each climax of the swing to balance with the gravitational pull of the earth core.I'd use a material such as copper for the variable.Also the weight distribution on the variables base plays a role.Take all the into account and experiment for a while!maybe one day you could find the right proportions in every role for kinetic potential gravitational momentum and weight to keep it going forever. As said alotta factors play a huge role in this experiment  <span />
3 0
3 years ago
Read 2 more answers
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