Answer:
The airliner travels 1.65 km along the runway before coming to a halt.
Explanation:
Given
Resistive forces = (2.90 × 10⁵) N = 290000 N
Mass of the airliner = (1.70 × 10⁵) kg = 170000 kg
Velocity of airliner = 75 m/s
Let the distance over moved by the airliner be equal to d
According to the work-energy theorem, the work done by the resistive forces in stopping the airliner is equal to the travelling kinetic energy of the airliner.
Work done by the resistive forces = (290000) × d = (290,000d) J
Kinetic energy of the airliner = (1/2)(170000)(75²) = 478,125,000 J
290000d = 478,125,000
d = (478,125,000/290,000)
d = 1648.7 m = 1.65 km
Hope this helps!!!
Answer:
I would make all the people depressed but that would be normal and all the happy people were considerd sped.
Explanation:
- R=ρ×L/A
ρ=R×A/L
A=pie(r²)=pie(0.6²)=pie(0.36)=1.13
ρ=2ohm×1.13mm²/1500mm
ρ=0.0015ohm.mm
2. we were told that the wires were made of the same substance so the resistivity(ρ)is the same for both wires so:
R=ρ×L/A
R=0.0015ohm.mm×500mm/0.09mm²
R=8.3'ohm
so our resistance for the second wire is :
<em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em>R</em><em>=</em><em>8</em><em>.</em><em>3</em><em>'</em><em>ohm</em>
Explanation:
It is given that,
Speed of the sports car, v = 85 mph = 37.99 m/s
The radius of curvature, r = 525 m
Let 
is the normal weight and 
is the apparent weight of the person. Its apparent weight is given by :
So, 
or
Hence, this is the required solution.
Answer:
kinetic energy
Explanation:
Kinetic energy is energy in motion
