Answer:
20 N
Explanation:
<em>Newton's second Law of motion</em> law states that If there is a external force acting on an object. Then the rate of change of momentum of that object is directly proportional to the force acting on its.
- the net force acting upon the object <em>(F)</em>
- the mass of the object. <em>(m)</em>
- <em>V </em>Final velocity of the object
- U initial velocity of the object
- mV -Final momentum of the object
- mU - Initial momentum of the object
Due to momentum change of that object, momentum change. We can write the equation bellow this,
F = (mV-mU)/t
When m is constant we can write the above expression like this,
F = m (V-U)/t
There for
(V-U)/t = a ( Rate of change of velocity can be denoted as acceleration )
F = m× a
we can state this in mathematically,
a = F/m
in another representation
F = m*a
Net Force = mass*acceleration
= 10 * 2
= 20 N
object is subjected to a negative acceleration due to the friction.
Explanation:
The liquid contains only one element. -The liquid is a pure substance. The number at the end of an isotope's name is the -mass number. While looking at xenon (Xe) on the periodic table, a student needs to find an element with a smaller atomic mass in the same group.
The answer is 0.000824653J
You need to use the formula Mass * Velocity^2 over 2
I assume the 100 N force is a pulling force directed up the incline.
The net forces on the block acting parallel and perpendicular to the incline are
∑ F[para] = 100 N - F[friction] = 0
∑ F[perp] = F[normal] - mg cos(30°) = 0
The friction in this case is the maximum static friction - the block is held at rest by static friction, and a minimum 100 N force is required to get the block to start sliding up the incline.
Then
F[friction] = 100 N
F[normal] = mg cos(30°) = (10 kg) (9.8 m/s²) cos(30°) ≈ 84.9 N
If µ is the coefficient of static friction, then
F[friction] = µ F[normal]
⇒ µ = (100 N) / (84.9 N) ≈ 1.2
