We may be positive that an object is in mechanical equilibrium if it is not rotating and experiences no acceleration.
<h3>What is 
mechanical equilibrium?</h3>
There are numerous other definitions for mechanical equilibrium that are all mathematically comparable in addition to the definition in terms of force. A system is in equilibrium in terms of momentum if the component motions are all constant. If velocity is constant, the system is in equilibrium in terms of velocity. When an item is in a state of rotational mechanical equilibrium, its angular momentum is preserved and its net torque is zero. More generally, equilibrium is reached in conservative systems at a configuration space location where the gradient of the potential energy concerning the generalized coordinates is zero.
To learn more about mechanical equilibrium, visit:
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Answer: True!
Explanation: The force is proportional to the square of the distance between 2 point masses
 
        
             
        
        
        
To solve this problem we will use the linear motion kinematic equations, for which the change of speed squared with the acceleration and the change of position. The acceleration in this case will be the same given by gravity, so our values would be given as,

Through the aforementioned formula we will have to

The particulate part of the rest, so the final speed would be



Now from Newton's second law we know that

Here,
m = mass
a = acceleration, which can also be written as a function of velocity and time, then

Replacing we have that,


Therefore the force that the water exert on the man is 1386.62
 
        
             
        
        
        
Answer:ask yo mama
Explanation:she finished school 
 
        
             
        
        
        
Answer:
    = 0.331 J / g ° C
 = 0.331 J / g ° C
Explanation:
We have a calorimetry exercise where all the heat yielded by one of the components is absorbed by the other.
Heat ceded          Qh = m1 ce1 ( -
 - )
)
Heat absorbed     Qc = m2 ce2 ( - T₀)
 - T₀)
Body 1 is metal and body 2 is water
.  Where m are the masses of the two bodies, ce their specific heat and T the temperatures
       Qh = Qc
       m₁  (
 ( -
-  ) = m₂
) = m₂   (
 ( - T₀)
 - T₀)
we clear the specific heat of the metal
        = m₂
 = m₂   (
 ( - T₀) / (m₁ (
 - T₀) / (m₁ ( -
- ))
))
       = 50.00 4.184 (20.15 -10.79) / (75.00 (99.0-20.15))
= 50.00 4.184 (20.15 -10.79) / (75.00 (99.0-20.15))
        = 209.2 (9.36) / (75 78.85)
 = 209.2 (9.36) / (75 78.85)
        = 1958.11 / 5913.75
 = 1958.11 / 5913.75
       = 0.331 J / g ° C
 = 0.331 J / g ° C