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miss Akunina [59]
3 years ago
6

If a child is on a bus and the ride is smooth they might not realize that they are moving unless they look out of a window.

Physics
1 answer:
Kruka [31]3 years ago
3 0

A. true because your brain can't tell your moving inless you look out side and it defentily can't tell if it is a smooth ride


you welcome : )

-jv

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If a non-rotating object has no acceleration, then we can say for certain that it is:__________
EleoNora [17]

We may be positive that an object is in mechanical equilibrium if it is not rotating and experiences no acceleration.

<h3>What is mechanical equilibrium?</h3>

There are numerous other definitions for mechanical equilibrium that are all mathematically comparable in addition to the definition in terms of force. A system is in equilibrium in terms of momentum if the component motions are all constant. If velocity is constant, the system is in equilibrium in terms of velocity. When an item is in a state of rotational mechanical equilibrium, its angular momentum is preserved and its net torque is zero. More generally, equilibrium is reached in conservative systems at a configuration space location where the gradient of the potential energy concerning the generalized coordinates is zero.

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6 0
2 years ago
The gravitational force between two objects is proportional to the square of the distance between the two objects.
Darina [25.2K]

Answer: True!

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3 0
3 years ago
An 89 kg man drops from rest on a diving board −3.1 m above the surface of the water and comes to rest 0.5 s after reaching the
OLga [1]

To solve this problem we will use the linear motion kinematic equations, for which the change of speed squared with the acceleration and the change of position. The acceleration in this case will be the same given by gravity, so our values would be given as,

m= 89 kg\\x = 3.1 m\\t = 0.5s\\a = g = 9.8m/s^2

Through the aforementioned formula we will have to

v_f^2-v_i^2 = 2ax

The particulate part of the rest, so the final speed would be

v_f^2 = 2gx

v_f=\sqrt{2(9.8)(3.1)}

v_f = 7.79m/s

Now from Newton's second law we know that

F = ma

Here,

m = mass

a = acceleration, which can also be written as a function of velocity and time, then

F = m\frac{dv}{dt}

Replacing we have that,

F = (89)\frac{7.79}{0.5}

F = 1386.62N

Therefore the force that the water exert on the man is 1386.62

3 0
3 years ago
Ten narrow slits are equally spaced 3.00 mm apart and illuminated with indigo light of wavelength 444 nm. The width of bright fr
ankoles [38]

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8 0
3 years ago
A 75.00 gram sample of an unknown metal initially at 99.0 degrees Celcius is added to 50.00 grams of water initially at 10.79 de
jeyben [28]

Answer:

  c_{e1} = 0.331 J / g ° C

Explanation:

We have a calorimetry exercise where all the heat yielded by one of the components is absorbed by the other.

Heat ceded          Qh = m1 ce1 (T_{h} -T_{f})

Heat absorbed     Qc = m2 ce2 (T_{f} - T₀)

Body 1 is metal and body 2 is water .  Where m are the masses of the two bodies, ce their specific heat and T the temperatures

      Qh = Qc

      m₁ c_{e1} (T_{h}- T_{f}) = m₂  c_{e2} (T_{f} - T₀)

we clear the specific heat of the metal

      c_{e1} = m₂  c_{e2} (T_{f} - T₀) / (m₁ (T_{h}-T_{f}))

     c_{e1}= 50.00 4.184 (20.15 -10.79) / (75.00 (99.0-20.15))

      c_{e1} = 209.2 (9.36) / (75 78.85)

      c_{e1} = 1958.11 / 5913.75

     c_{e1} = 0.331 J / g ° C

5 0
3 years ago
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