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3 years ago

What is the speed of a wave with a frequency of 100 hz and a wave length of .5 m?

Physics

2 answers:

____ [38]3 years ago

7 0

Answer:

Explanation:

There are 2 ways to help with this. Explain the details, which are fairly simple in this topic, or give the formula. My hope is that an explanation will last longer than memorizing the formula. I give you both.

If a wave has frequency, f, of 3 Hz, its period, T, is

. The wavelength,

, is 5 meters. That means that in the time of one period, the wave travels 5 m.

In general,

distance

time

In applying this general definition of speed

↑

to a wave, we have

speed of the wave

wavelength

period

Note: we generally use v for speed of a wave. Using the variable names, then that last formula is written

Since

, we can also say that

⋅

So, using that last formula

⋅

Note: the unit Hz is equivalent to what it was called 100 years ago,

cycles

second

(

also cps

)

. Cycles is not a true unit, so the Hz contributed only the "per second" to the result

ElenaW [278]3 years ago

4 0

Answer: the speed is =30ms^-1 The speed of a wave is given by "speed" (ms^-1)= "frequency(Hz)" xx "wavelength (m)" The frequency is f=100Hz The wavelength is lambda=0.3m The speed is v=lambdaf=0.3*100=30ms^-1

Explanation:

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A mass spectrometer applies a voltage of 2.00 kV to accelerate a singly charged positive ion. A magnetic field of B = 0.400 T th

N76 [4]

The mass of the ion is 5.96 X 10⁻²⁵ kg

<u>Explanation:</u>

The electrical energy given to the ion Vq will be changed into kinetic energy $\frac{1}{2}mv^2$

As the ion moves with velocity v in a magnetic field B then the magnetic Lorentz force Bqv will be balanced by centrifugal force $\frac{mv^2}{r}$ .

So,

$Vq = \frac{1}{2}mv^2$

and

$Bqv = \frac{mv^2}{r}$

Right from these eliminating v, we can derive

$m = \frac{B^2r^2q}{2V}$

On substituting the value, we get:

$m = \frac{(0.4)^2X (0.305)^2 X1.602X 10^-^1^9}{2X 2000}\\\\$

m = 5.96 X 10⁻²⁵ kg.

3 0

3 years ago

Why might an electromagnet be used to pick up old cars in junkyards?

siniylev [52]

B) Hope it helps ,Have a nice day :)

7 0

3 years ago

Read 2 more answers

If the Sun were the size of a small exercise ball (about 0.5 meters (m) in

suter [353]

Answer:

the size of a pea

Explanation:

4 0

2 years ago

Firemen are shooting a stream of water at a burning building. A high-pressure hose shoots out the water with a speed of 26.0 m/s

alekssr [168]

Answer:

a) θ = 58.3º

b) vfh = 13.7 m/s

c) g = -9.8 m/s2

d) h = 22.2 m

e) vfb = 15.5 m/s

Explanation:

Assuming that gravity is the only influence that causes an acceleration to the water, due to it is always downward, since both directions are independent each other, in the horizontal direction, the water moves at a constant speed.
Since the velocity vector has a magnitude of 26.0 m/s, we can find its horizontal component as follows:
vₓ₀ = v * cos θ (1)
where θ is the angle between the water and the horizontal axis (which we define as the x-axis, being positive to the right).
Applying the definition of average velocity, taking the end of the hose like the origin, and making t₀ = 0, we can write the following expression:

$x_{f} = v_{ox} * t = v_{o} * cos \theta * t (2)$

Replacing by the givens of xf = 41.0m, t = 3.00 s, and v=26.0 m/s, we can solve for the angle of elevation θ, as follows:

$cos \theta = \frac{x_{f} }{v*t} = \frac{41.0m}{26.0m/s*3.00s} = 0.526 (3)$

⇒θ = cos⁻¹ (0.526) = 58.3º (4)

At the highest point in its trajectory, just before starting to fall, the vertical component of the velocity is just zero.
Since the horizontal component keeps constant during all the journey, we can conclude that the speed at this point is just v₀ₓ, that we can find easily from (1) replacing by the values of v and cos θ, as follows:
vₓ₀ = v * cos θ = 26.0 m/s * 0.526 = 13.7 m/s. (5)

At any point in the trajectory, the only acceleration present is due to the action of gravity, which accepted value is -9.8 m/s2 (taking the upward direction on the vertical y-axis as positive)

Since we know the time when the water strikes the building, it will be the same for the vertical movement, so, we can use the kinematic equation for vertical displacement, as follows:

$\Delta y = v_{oy} * t - \frac{1}{2} *g*t^{2} (6)$

Our only unknown remains v₀y, which can be obtained in the same way than the horizontal component:
v₀y = v * sin θ = 26.0 m/s * 0.85 = 22.1 m/s (7)
Replacing (7) in (6), we get:

$\Delta y = 22.1 m/s* 3.0s - \frac{1}{2} *9.8m/s2*(3.00s)^{2} = 22.2 m (8)$

When the water hits the building the velocity vector, has two components, the horizontal vₓ and the vertical vy.
The horizontal component, since it keeps constant, is just v₀x:
v₀ₓ = 13.7 m/s
The vertical component can be found applying the definition of acceleration (g in this case), solving for the final velocity, as follows:

$v_{fy} = v_{oy} - g*t (9)$

Replacing by the time t (a given), g, and v₀y from (7), we can solve (9) as follows:

$v_{fy} = 22.1 m/s - 9.8m/s2*3.00s = -7.3 m/s (10)$

Since we know the values of both components (perpendicular each other), we can find the magnitude of the velocity vector (the speed, i.e. how fast is it moving), applying the Pythagorean Theorem to v₀ₓ and v₀y, as follows:

$v_{f} = \sqrt{(13.7m/s)^{2} +(-7.3m/s)^{2}} = 15.5 m/s (11)$

3 0

3 years ago

Do balanced forces change an objects motion

meriva

If the group of all forces acting on an object is balanced,
then the effect of all of them is the same as if there were
no forces at all on the object. In that case, the object
continues moving in a straight line at a constant speed.

8 0

3 years ago